What is Velocity at t=5s? Answer with Units

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Homework Help Overview

The discussion revolves around determining the velocity at a specific time, t = 5 seconds, based on a provided graph. The participants are exploring the concept of instantaneous velocity and its calculation using the slope of the graph.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants attempt various calculations involving distance and time but express confusion about the correct method to find velocity. Questions arise regarding the interpretation of the slope of the graph and how to apply it to find the instantaneous velocity at t = 5 seconds.

Discussion Status

There is an ongoing exploration of how to calculate the slope between specific points on the graph to determine velocity. Some participants have offered guidance on focusing on the change in position over time, while others express uncertainty about the calculations and the correct approach.

Contextual Notes

Participants are working with a graph that is not visible in the thread, which may limit their ability to accurately assess the slope and thus the velocity. There is also mention of specific values and time intervals that are being debated, contributing to the confusion.

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Homework Statement


Tell me precisely what the velocity is when the time t = 5 seconds. include the appropriate units in your answer

the picture of the problem is here click the link then zoom into see the actual queston
http://img372.imageshack.us/img372/7473/43121337ma9.th.jpg

Homework Equations





The Attempt at a Solution



I tried adding the full distance divded by 5 but the answers wrong, i aslo tried subtracting the distance then divding by the time still wrong

then i assumed that it was just the distance by it self 200 divded by 5 but that's all wrong
 
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NukeNuke said:

Homework Statement


Tell me precisely what the velocity is when the time t = 5 seconds. include the appropriate units in your answer


The Attempt at a Solution



I tried adding the full distance divded by 5 but the answers wrong, i aslo tried subtracting the distance then divding by the time still wrong

then i assumed that it was just the distance by it self 200 divded by 5 but that's all wrong

Velocity is the instantaneous rate of change of distance at a particular time.

That would be given on you graph by the slope of the line at the time asked.

Figure the slope at t=5.
 
LowlyPion said:
Velocity is the instantaneous rate of change of distance at a particular time.

That would be given on you graph by the slope of the line at the time asked.

Figure the slope at t=5.

okay so its 200 then what?

should i divide 200 by 5 or multiply it by 5 I am lost at this point
 
Last edited:
NukeNuke said:
okay so its 200 then what?

should i divide 200 by 5 or multiply it by 5 I am lost at this point

What is the slope of the graph at 5?

Not the value at 5 ... the slope.

How much does it CHANGE between 4 and 6 ?
 
LowlyPion said:
What is the slope of the graph at 5?

Not the value at 5 ... the slope.

How much does it CHANGE between 4 and 6 ?

it changes 200 that's the difference
 
NukeNuke said:
This must be were I am lost at cause i have no idea what I am looking for,

The final position for your purpose at 6 is what?
The initial position at 4 is what?

The rate of change of position is Final Position less Initial Position divided by the time to change position. So figure the time difference and divide the change in position. That is your velocity. That is also the slope of the graph at all points between 4 and 6 and hence that is the velocity at all times between 4 and 6 seconds.
 
NukeNuke said:
it changes 200 that's the difference

Not exactly. It changes (-200).

And the time is what? 2 seconds?

That means that Velocity is -200m/2s = -100 m/s
 
O..okay thanks for the help
 

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