What is x^i? How can you rewrite it?

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Very simple question... What is x^i? How can you rewrite it?
All I could figure out is that (x^i)^i = 1/x, but that doesn't help much
Wolfram Alpha gave me this graph (real part in blue, imaginary in orange)
http://www4c.wolframalpha.com/Calculate/MSP/MSP17119i95eid65h0gce900001e7b96h101dd87d6?MSPStoreType=image/gif&s=62&w=320&h=119&cdf=RangeControl
Which is a very strange graph.

What happens?
 
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It is probably clearer if you look at it in the complex plane.
Apart from that, what happens is exactly what the graph says happens.

consider:
[itex]e^{i\theta}[/itex] is just the unit vector rotated anti-clockwise in the complex plane by [itex]\theta[/itex] radiens.

[itex]a^b = e^{b\ln{a}}[/itex] so [itex]x^i = e^{i\ln{x}}[/itex] so [itex]x^i[/itex] is the unit vector rotated by ln(x) radiens in the complex plane.
 
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Simon Bridge said:
It is probably clearer if you look at it in the complex plane.
Apart from that, what happens is exactly what the graph says happens.

Okay, so wolfram alpha says that 3^i is about 0.455 + 0.890i
How did it figure that out?
 


Ah - you posted while I edited: that's a bad habit of mine.
It's a rotation in the complex plane.
The real part is the cos(ln(x)) and the imaginary part is sin(ln(x))
 
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That made so much more sense than I expected it to.
It also explains this graph of y=Re(x^i)^2+Im(x^i)^2
http://www4b.wolframalpha.com/Calculate/MSP/MSP237219i95h4480ahf33i00001h6c277de8811fe7?MSPStoreType=image/gif&s=34&w=307&h=136&cdf=RangeControl
Friggin' beautiful.
 
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Yep - when you get used to rotating phasors lots of things get simple.
I dredged up a link for you. It covers the whole imaginary exponent thing (like what happens when you raise a complex number to the power of another complex number) then links to a bunch of applications.

It's also used in analyzing linear networks (electronics) and anything with waves.
 

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