What Mechanism Explains the Rate Law for 2A + B2 -> 2AB?

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SUMMARY

The rate law for the reaction 2A + B2 → 2AB is defined as Rate = k[A][B2]. The proposed mechanism involves two elementary steps: the first step is A + B2 → AB + B, followed by B + A → AB. This mechanism aligns with the rate law, indicating that the slow steps involve one mole of A and one mole of B2, confirming the stoichiometry of the rate law. The discussion emphasizes the importance of understanding reaction mechanisms in relation to rate laws.

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Homework Statement



"Given the rate law for the following equation is Rate = k[A][B2]
2A + B2 ------> 2AB

Suggest a mechanism for the reaction


Homework Equations



I have no clue; I was absent for 2 weeks and now have to teach myself the first two units, I've been able to teach myself rate law and order of the reaction and equilibrium stuff but I am lost on this.

The Attempt at a Solution



A + B = AB
AB + AB = 2AB

Any guidance would be nice.
 
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I'm also a student but I'm going to try this, since the rate law stated that Rate = k[A][B2] so my assumption is

A + B2 ---> AB + B
B + A ----> AB

since the rate law is Rate = k[A][B2] it should means that the slow steps consist of 1 mol of A and 1 mol of B2
 

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