- #1

JD003

- 3

- 0

0 = ax + bx + c then factor for the zeros/solutions

(d) distance would be 0. But how do I put, (v) mph, with 0.0074v² ? More correctly asked I suppose is how do I separate it? If I simply plug v in, using #1. as the example, I see 0.0074(80)² and I know that's not getting me anywhere.

Thanks for any time you may have to help On a certain type of street surface, the equation d = 0.0074v² can be used to approximate the stopping distance d, in feet, a car traveling at a

speed of v miles per hour will need when its brakes are applied.

1. What is the cars stopping distance if its speed is 80 miles per hour?

The stopping distance would be ___ ft. (Round to nearest whole number.)

2. What is the cars stopping distance if its speed is 65 miles per hour?

The stopping distance would be ___ ft. (Round to nearest whole number.)

3. A car was in an accident. When the traffic officer got to the scene, he noticed the length of the skid mark left by the car. The officer measured the stopping

distance and concluded that driver need 41 ft. to stop after applying the brakes. At what speed was the car going?

The speed of the car was ___ mph.

4. Did the officer issue the car owner a ticket for speeding if the speed limit was 65 mph.

O A. No

O B. Yes