What Steps Are Needed to Solve This Trigonometric Function?

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Factor cos^2x-sin^2x and then you can factor out a (sinx-cosx). See if that helps.
 
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Factor out a -1 out of one of the terms!
 
^

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now u can factor :)
 

Thread 'Finding the nth roots of a complex number'

There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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