What Value of p Maximizes the Variance of X?

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SUMMARY

The discussion focuses on maximizing the variance of the random variable X defined by the probabilities P(X=0) = P(X=2) = p and P(X=1) = 1-2p, where 0 ≤ p ≤ 1/2. The variance Var(X) is expressed as a function of p, specifically Var(X) = E[X^2] - (E[X])^2. By calculating the expected values and differentiating the variance function with respect to p, the maximum variance occurs at p = 1/6.

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TomJerry
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Let the random variable X have the distribution

[itex]P(X=0) = P(=2) = p[/itex]

[itex]P(X=1) = 1-2p,[/itex] [itex]0 \le p \le \frac{1}{2}[/itex]

For what p is Var X maximum
 
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Write down the expression for the variance - it will be a function of p. Maximize that function.
 

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