MHB What Values of k Make These Vectors Linearly Dependent?

  • Thread starter Thread starter Yankel
  • Start date Start date
  • Tags Tags
    Linear Vectors
Yankel
Messages
390
Reaction score
0
I have 4 vectors:

(1,1,1,k), (1,1,k,1), (1,k,1,1), (k,1,1,1)

I need to find out for which values of k (if any) the vectors will be dependent.

I put them all to a matrix, and reduced it using the Gaussian method (homogeneous system). I received:

1st row: 1 1 1 k 0

2nd row: 0 (k-1) 0 (1-k) 0

3rd: 0 0 (k-1) (1-k) 0

4th: 0 0 0 (-2k+3-x^2) 0the reduction is correct, I verified with MAPLE.

I am stuck here, MAPLE say the solution is (0,0,0,0), meaning that the vectors are independent, but on the other hand, when I do it manually, I think is has a solution, for example, the last equation is:

(-2k+3-x^2)*x4=0

it can be either when x4 is 0 or when k is 1 or -3. I am confused...(Worried) :confused:
 
Physics news on Phys.org
What are x and x4?

When k=1 all the vectors are equal, so that's a solution.
When k=-3 the sum of the vectors is the null vector, so that's also a solution.
 
Last edited:
ah, sorry, confused x with k.

when k=1,-3 the system has infinite number of solutions, right ? so for these values the vectors are dependent...got it now, thanks !
 
Thread 'How to define a vector field?'
Hello! In one book I saw that function ##V## of 3 variables ##V_x, V_y, V_z## (vector field in 3D) can be decomposed in a Taylor series without higher-order terms (partial derivative of second power and higher) at point ##(0,0,0)## such way: I think so: higher-order terms can be neglected because partial derivative of second power and higher are equal to 0. Is this true? And how to define vector field correctly for this case? (In the book I found nothing and my attempt was wrong...

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K