What Wavelength of Light Removes an Electron from Tin?

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SUMMARY

The discussion centers on calculating the wavelength of light required to remove an electron from a gaseous atom of tin (Sn). The user employs Planck's constant (6.62 x 10-34 J.s) and the speed of light (3 x 108 m/s) to derive the energy needed for ionization using the formula ΔE = hc/λ. The user mistakenly attempts to apply the de Broglie equation (λ = h/mv) with the mass of tin instead of the ionization energy, leading to an incorrect wavelength calculation of 1.86 x 10-41 m. The correct approach emphasizes the importance of ionization energy over mass in this context.

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sami23
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What wavelength of light would be required to remove an electron from a gaseous atom of tin?

Here, I used Plank's constant h as 6.62*10-34 J.s and Constant c as 3*108 m/s

Also, energy needed to remove an electron is calculated by \DeltaE =hc/\lambda

I also used Broglie Eqn: \lambda = h/mv

The mass of Sn is 118.710 g. --> 0.11871 kg What is the mass of an electron of tin?

Can I use Broglie's Eqn and state that the wavelength required is:
6.62*10-34 J.s / ((0.11871 kg)*(3*108 m/s))

=1.86*10-41 m

This doesn't seem right. Please help.
 
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Masses are irrelevant, you will need ionisation energy.

No idea what you mean by "electron of tin". All electrons are identical.
 

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