What will the profit be if 1500 units are sold next year?

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The discussion centers on calculating the profit for a small company expecting to sell 1500 units next year. The company incurred a loss of $5000 in its first year, with fixed costs of $15,000 and a marginal cost of $80 per unit. The profit function is defined as P(p,x) = (p-80)x - 15000. By determining the selling price per unit (p) from the previous year's sales of 500 units, the profit for selling 1500 units can be accurately calculated using this function.

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the first year of operation for a small company yielded a loss of \$5000. The company has \$15,000 per year tied up in fixed costs and spent 40,000 on raw materials and labour. Since the company was not well known, they were only able to sell 500 units of their product that year. It is hoped that business with improve next year and that 1500 units will be sold at the same selling price as last year.

a) If 1500 units are sold next year, what will the profit be?
 
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Profit is revenue less costs. There is a fixed cost of 15000 and a marginal cost of 80...if we denote the price of each unit as $p$ and the number of units sold as $x$, then our profit function $P$ is:

$$P(p,x)=px-\left(80x+15000\right)=(p-80)x-15000$$

Now, we are given:

$$P(p,500)=(p-80)500-15000=-5000$$

So, what is $p$?
 
I was taught a different way for this module. I was taught to have a chart with Unit basis and total amount at the top and on the left side we have s, vc, cm, fc, and np and we fill in the numbers.
 
Well, you're in for a treat then, as I'm going to help you answer this question in a much easier and more straightforward manner using a little algebra. (Yes)

Once you find $p$, then you will have the profit function in one variable $x$, into which you can simply plug the given value of $x$ to output the profit for that production level. No time consuming charts, graphs and/or tables required. (Bow)
 

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