The discussion centers on determining the speed of a charge required for the electric force to equal the magnetic force in an electric field of 2.1 x 10^8 N/C and a magnetic field of 0.90 T. The relationship between electric force (F_e) and magnetic force (F_m) is established through the equation F_e = qE and F_m = qvB, where q is the charge, E is the electric field strength, v is the velocity of the charge, and B is the magnetic field strength. Setting these forces equal allows for the calculation of the necessary speed, leading to the formula v = E/B.
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Thehumbleguy said:An area has an electric field of 2.1*10^8N/C and a Mag. field of 0.90T. What would be the speed of the charge have to be to go into the area in order for the electric force on the charge equal the magnetic force on the charge?
I am unsure how to approach this question ...can someone please help?!