# What would be the truck's skidding distance?

i was actually preparing a small project on maxwell so i registered here. and stumbled on u by accident lol

Okay, if you increase the mass, you also increase the normal force so that the frictional force increases as you increase the mass, and there is no change in the acceleration regardless of the mass.

$$-\mu mg=ma$$
$$-ug = a$$

The acceleration is independent of the mass.

lmao i m not like lil puppet dat u can stumble on mee !!!!! lolzz ANYWAYSS THANX ALOT EVERYONE FOR CONFUSING ME!!! lmao now i feel stupid

Okay, if you increase the mass, you also increase the normal force so that the frictional force increases as you increase the mass, and there is no change in the acceleration regardless of the mass.

$$-\mu mg=ma$$
$$-ug = a$$

The acceleration is independent of the mass.

thats not what newton's second law states and where did u get those equations from.

hehe i didn mean it that way really. i just tried to help i pressed on ur force tab and there u were wit the question
anyways i was just tryin to help... take care

now helpp!!! nooo lolzz dnt go lmao since you have the right answer i think.

The frictional force is dependent on the mass, the coefficient of static friction, and the acceleration due to gravity, but the deceleration of the truck isn't dependent on the mass AS YOU CAN SEE WITH THE EQUATION. If you can't see that through the cancelling of the mass on both sides of the equation, then you can't move on and your answer will be wrong just as it is right now, with your teacher telling you that it is wrong.

but would nt the equations be F=ma and F=2ma and that cancels out the ma leaving behind a 2?

ya so the force doubles

But what is F? F is the frictional force. There are no other forces acting in the direction of motion except the frictional force as I've stated numerous times before. What is the frictional force? It is uF_n where u is the coefficient of friction. What is F_n? It is equal to mg.

Put it all together and you get -umg = ma.

no no ur wrong f1 = ma
f2 = 2ma
f1 is not equal to f2

Okay, I give up. If anyone wants to take over, go ahead.

ok i plugged in numbers and i got that the displacement would be 2x

ok then 2x when i said 4 x i was still thinkin acc would change

so its 2x?? YAYYY!! i understood something finallY!!! awww snazzyy gives up on me :(

and acc's time squares so..
so u got it now

NO, IT IS NOT 2X. THE MASS CANCELS OUT ON BOTH SIDES OF THE EQUATION.

THIS EQUATION, RIGHT HERE:

$$-\mu mg = ma$$

$$-\mu g =a$$

THE DECELERATION DOES NOT DEPEND ON THE MASS.

Does that help?

hmm... not really nd omg relaxxx ur typing in caps calmmm downnnnnn

Well then, you were destined to get this question wrong.

wait a sec let me solve it a bit