A hunter wanted to know the air temperature. The echo from a nearby cliff returned 1.5 s after he fired his riffle. If the cliff is 250 m away, how do you calculate the air temperature?
v=331 m/s + (0.59 m/s/c˚)T niSinθi=nRSinθR x=Δd/2 These eq'ns might be useful
The Attempt at a Solution
x=250 m/2 = 125
v=125 m/1.5s = 83.33 m/s
83.33 m/s = 331 m/s + (0.59 m/s/c˚)T