What's the air temperature when Δd=250m

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SUMMARY

The discussion centers on calculating the air temperature based on the time it takes for an echo to return from a cliff 250 meters away. The hunter measured an echo return time of 1.5 seconds, leading to a calculated speed of sound of 83.33 m/s. Using the equation v = 331 m/s + (0.59 m/s/°C)T, the temperature can be derived by rearranging the formula to solve for T. The distance traveled by the sound wave is confirmed to be 250 meters, as the echo reflects back to the hunter.

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Homework Statement



A hunter wanted to know the air temperature. The echo from a nearby cliff returned 1.5 s after he fired his riffle. If the cliff is 250 m away, how do you calculate the air temperature?

Homework Equations



v=331 m/s + (0.59 m/s/c˚)T niSinθi=nRSinθR x=Δd/2 These eq'ns might be useful

The Attempt at a Solution



x=250 m/2 = 125
v=125 m/1.5s = 83.33 m/s
83.33 m/s = 331 m/s + (0.59 m/s/c˚)T
 
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why you used x = 125??

what is the distance traveled by sound wave in the whole process?
 

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