What's the excitation temp of He? How to get this?(DBD plasma)

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SUMMARY

The excitation temperature of helium (He-1) in dielectric barrier discharge (DBD) plasma can exceed 1000K, as determined through calculations based on high-intensity wavelengths of 588nm, 668nm, and 708nm. The relationship between ln(a) and temperature is defined by the formula ln(a) ∝ -1/(T-ex), where 'a' represents wavelength intensity. In DBD plasma, while the gas temperature remains around 300-400K, the electrons achieve higher energy levels due to the electrical field, resulting in a non-equilibrium state that facilitates radiation emission.

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  • Understanding of DBD plasma physics
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  • Knowledge of helium spectral lines and their intensities
  • Basic principles of non-equilibrium plasma behavior
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Lh0907
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Hello.

I've experiment, which makes plasma using He-1 under atmoshpere & room temp,it's to show how DBD plasma emission energy.

As I know that high intensity wave length of He-1 are 588nm,668nm,708nm..etc.

If take a formula, ln(a) is propotional to -1/(T-ex). ln(a) is some value.(a has wave length,intensity..etc).

To calculate excitation temp, I read a paper which pick up non-degeneracy wave length(to claer select high intensity wave length).

I've got a calculation T-ex, which is over 1000K.(Energy level 1s 1s2p -1s3d)

Is the right? (As I know, energy gap is around 0.3~0.7eV. But Is it also maintain under
DBD plasma?
 
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That is why it is called a non-equilibrium plasma. The gas in the DBD is in equilibrium and has a temperature of 300-400k but the electrons are not in equibrium. The electrons are heated by the electrical field and the DBD contains hot electrons that have energies of several eV. It is these electrons that create the radiation by impact on He