When you drive a .36 kg apple, Earth exerts a force on It that accelerates it at 9.8 m/s squared toward the earths surface. According to newtons third law the Apple must exert an equal but opposite force on earth. If the mass of the earth is 5.89x10^24 kg,what is the magnitude of the earth's acceleration toward the apple? I have tried this problem a couple of times and get it wrong. My math is: .36*9.8/5.98x10^24.