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Help on physics problem:distance Earth moves towards the apple

  1. Nov 30, 2012 #1
    1. The problem statement, all variables and given/known data
    When you drop a 400g apple, earth exerts a force that accelerates it at -9.80m/s^2.
    The mass of the earth is 5.98*10^24kg.
    The acceleration of the earth as it falls towards the apple is 6.56 • 10^-25m/s^2.
    if the apple falls from a height of 5.00m, find the distance the earth moves.


    2. Relevant equations
    vf^2=vi^2+2ad
    t=2d/vi+vf


    3. The attempt at a solution
    I found the final velocity(9.90m/s) of the apple and the time it took (1.01s).
    But how do I find the distance the earth moves with only its acceleration?
     
  2. jcsd
  3. Nov 30, 2012 #2
    You have time, acceleration, and you can infer initial velocity. Look at your other kinematic equations.
     
  4. Nov 30, 2012 #3
    so can I use the formula d=vit+1/2at^2?
    will the intital velocity be 0 or 9.90m/s?
     
  5. Nov 30, 2012 #4
    The initial velocity is 0 m/s.
     
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