When you drive a .36 kg apple, Earth exerts a force on It that

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SUMMARY

When a 0.36 kg apple is driven towards Earth, it experiences an acceleration of 9.8 m/s² due to Earth's gravitational force. According to Newton's third law, the apple exerts an equal and opposite force on Earth. To calculate the Earth's acceleration towards the apple, the formula F = ma is applied, where the force exerted by the apple on Earth is equal to its mass multiplied by the gravitational acceleration. Given Earth's mass of 5.89 x 1024 kg, the acceleration can be determined using the relationship derived from Newton's laws.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic algebra for manipulating equations
  • Knowledge of gravitational acceleration (9.8 m/s²)
  • Familiarity with mass units (kg) and scientific notation
NEXT STEPS
  • Calculate the acceleration of Earth using the formula F = ma with the given values
  • Explore Newton's third law of motion in more detail
  • Study gravitational force calculations in different mass scenarios
  • Learn about the implications of mass and acceleration in physics
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Students studying physics, educators teaching mechanics, and anyone interested in understanding gravitational interactions and Newton's laws.

KellySierra22
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When you drive a .36 kg apple, Earth exerts a force on It that accelerates it at 9.8 m/s squared toward the Earth's surface. According to Newtons third law the Apple must exert an equal but opposite force on earth. If the mass of the Earth is 5.89x10^24 kg,what is the magnitude of the Earth's acceleration toward the apple?

I have tried this problem a couple of times and get it wrong. My math is: .36*9.8/5.98x10^24.
 
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Hello KellySierra22,
Instead of giving your workings with numbers, it is easier to understand the problem in algebra.

We start with the well known F=ma, however we must be careful about which force and which mass (although the acceleration is constant). So I label them

F_{apple \rightarrow earth}= m_{apple} \times g_{apple \rightarrow earth}

That is the force the Earth exerts on the apple is the mass of the apple times acceleration, you must calculate this force first. Now that you have done so we can use Newtons third law

F_{apple \rightarrow earth}=F_{earth \rightarrow apple}

It may help to draw this pictorially. So you now have an equation relating the force you already have to the force the apple exerts on the earth. You can now calculate the acceleration on the Earth from the apple using

F_{earth \rightarrow apple}= m_{earth} \times g_{earth \rightarrow apple}

You must solve for the acceleration of the Earth towards the apple.
 


KellySierra22 said:
When you drive a .36 kg apple, Earth exerts a force on It that accelerates it at 9.8 m/s squared toward the Earth's surface. According to Newtons third law the Apple must exert an equal but opposite force on earth. If the mass of the Earth is 5.89x10^24 kg,what is the magnitude of the Earth's acceleration toward the apple?

I have tried this problem a couple of times and get it wrong. My math is: .36*9.8/5.98x10^24.

Hello KellySierra22, Welcome to Physics Forums.

The expression that you have shown should give you the numerical value for the acceleration of the Earth towards the apple. What value did you obtain when you completed the math?
 

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