Where Am I Going Wrong with Kahler Metric Computations?

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SUMMARY

The discussion focuses on the computation of the Kahler metric and potential in the context of string theory, specifically referencing the paper "0611332.pdf". The user initially struggles with the inverse of the Kahler metric, K^{a\bar{b}}, and its relation to the potential V_F(T). After several attempts, they realize that the correct form of the Kahler potential includes an additional term, leading to the conclusion that the term involving the integral over the Calabi-Yau manifold does not affect the Kahler metric but influences the potential. This insight clarifies the discrepancy in their calculations.

PREREQUISITES
  • Understanding of Kahler geometry and metrics in string theory
  • Familiarity with the concepts of potential energy in supersymmetric theories
  • Knowledge of Calabi-Yau manifolds and their integrals
  • Proficiency in algebraic manipulation of complex functions
NEXT STEPS
  • Study the derivation of the Kahler potential in string theory, focusing on the equations in the referenced paper.
  • Learn about the significance of the term \(\ln \left( -i \int_{CY_{3}}\bar{\Omega} \wedge \Omega \right)\) in the context of Kahler metrics.
  • Explore the relationship between the Kahler potential and the resulting vacuum states in supersymmetric models.
  • Investigate the implications of the singularity in the potential V_F and its role in vacuum uplifting scenarios.
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The discussion is beneficial for theoretical physicists, particularly those specializing in string theory, supersymmetry, and complex geometry, as well as graduate students seeking to deepen their understanding of Kahler metrics and potentials in high-energy physics.

AlphaNumeric
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I'm attempting to reproduce the results in http://arxiv.org/PS_cache/hep-th/pdf/0611/0611332.pdf , notably the V_F(T) potential involved with the Kahler potential

K = -2 \ln \left( \hat{\mathcal{V}} + \frac{\hat{\xi}}{2} \right)
W = W_{0} + Ae^{-aT}
\hat{\mathcal{V}} = \gamma (T+\bar{T})^{\frac{3}{2}}
\hat{\xi} = \xi (S+\bar{S})^{\frac{3}{2}}

Firsly I compute K_ab' using

K_{a\bar{b}} = \frac{\partial^{2}K}{\partial \phi^{a} \partial \bar{\phi}^{b}}

This gives me

K_{a\bar{b}} = \left(\frac{1}{\hat{\mathcal{V}} + \frac{\hat{\xi}}{2}}\right)^{2} \left( \begin{array}{cc} -\frac{3}{4} \gamma^{\frac{4}{3}} \hat{\mathcal{V}}^{-\frac{1}{3}}(\hat{\xi}-4\hat{\mathcal{V}}) & \frac{9}{4}(\xi \gamma)^{\frac{2}{3}} (\hat{\mathcal{V}}\hat{\xi})^{\frac{1}{3}} \\ \frac{9}{4}(\xi \gamma)^{\frac{2}{3}} (\hat{\mathcal{V}}\hat{\xi})^{\frac{1}{3}} & \frac{3}{4}\xi^{\frac{4}{3}}\hat{\xi}^{-\frac{1}{3}}(\hat{\xi}-\hat{\mathcal{V}}) \end{array} \right)

(god that's a pain to type!)

The problem is, when computing the inverse of this metric K^{a\bar{b}}, I don't get the quoted form of the paper (which is also used in several other papers by Quevado), which gives each entry of the metric being proportional to

\frac{1}{\hat{\xi}-\hat{\mathcal{V}}}

This gives an important result for Westphal, since the potential V_F turns out to have this same singularity and it gives a vacuum uplifting. If only I could get that far :rolleyes: I'm guessing it's the det of K_ab' which gives that factor, but that's not what I get when I compute |K_ab'| to get K^ab'.

Where am I going wrong? Am I neglecting a term I shouldn't in section 2 (equations 2.5 through to 2.7) or is it just I've slipped up on the algebra. I've done it about 10 times and still get the same. Given the symmetry between \hat{\xi} and \hat{\mathcal{V}} the Kahler metric has the right form, taking account of the factor of 2 here and there due to the 1/2 in the Kahler potential for xi-hat, so I'm at a lose to see anything obvious I've done wrong unless there's some fundamental result in the theory which I've missed or I've misunderstood the paper itself (both pretty likely knowing me!).

Thanks for any help :)
 
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I realized my error. Westphal doesn't explain that while there's a correct to one of the terms in (2.3) to the form of (2.5), the other terms in (2.3) remain, so the full Kahler potential is not that given in (2.5) but actually the ammendment (2.5) to (2.3) giving

K = -2 \ln \left ( \hat{\mathcal{V}} + \alpha '^{3}\frac{\hat{\xi}}{2}\right) - \frac{2}{3}\ln \hat{\xi} - \ln \left( -i \int_{CY_{3}}\bar{\Omega} \wedge \Omega \right)

Dropping the 3rd term in that potential and computing V_{F} gives the results given by Westphal and Quevado. I'm not exactly sure why the 3rd term no longer plays a part. If independent of T and S, it doesn't contribute to the Kahler metric, but it does to the potential, because the potential involves e^{K}. It doesn't alter the value of T which gives V_{F}=0 but it does alter V_{F} otherwise, given it multiplies the entire potential.

Can someone explain to me why I can essentially ignore the \ln \left( -i \int_{CY_{3}}\bar{\Omega} \wedge \Omega \right) term? Thanks.
 

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