Where can I test LaTex without disrupting discussions?

  • Context: LaTeX 
  • Thread starter Thread starter Hollysmoke
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    Latex Mind Testing
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Discussion Overview

The discussion revolves around testing LaTeX formatting within a forum thread. Participants share various mathematical expressions using LaTeX syntax, exploring different representations and manipulations of algebraic fractions.

Discussion Character

  • Exploratory
  • Mathematical reasoning

Main Points Raised

  • Participants present multiple mathematical expressions using LaTeX, including fractions and polynomial factorizations.
  • Some participants attempt to refine or correct LaTeX syntax in their expressions, indicating a focus on proper formatting.
  • A later reply suggests that there is a dedicated thread for testing LaTeX, encouraging participants to use that space instead of the current thread.

Areas of Agreement / Disagreement

There is no consensus on the appropriateness of the current thread for LaTeX testing, as one participant suggests moving such discussions to a designated thread.

Contextual Notes

Participants do not clarify the limitations of their LaTeX expressions, nor do they address any unresolved issues regarding syntax or mathematical accuracy.

Hollysmoke
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x^2-6x-7/2x^2+3x +1
 
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\frac{x^2-6x-7}{2x^2+3x+1}
 
\frac{x^2-6x-7}{2x^2+3x+1} x \frac{x^2-6x-7}{2x^2+3x+1} / \frac{x^2-6x-7}{2x^2+3x+1}
 
\frac{x^2-6x-7}{2x^2+3x+1} x \frac{4x^2-16x+15}{2x^2-17x+21} / \frac{4x^2-20x+25}{4x^2-1}
 
\frac{(x-7)(x+1)}{(2x+1)(x+1)} x \frac{(2x-5)(2x-3)}{2x-3)(x-7)} x \frac{2x+1)(2x-1)}{(2x-5)(2x+5)}
 
\frac{(x-7)(x+1)}{(2x+1)(x+1)} x \frac{(2x-5)(2x-3)}{(2x-3)(x-7)} x \frac{2x+1)(2x-1)}{(2x-5)(2x+5)}
 
\frac{(x-7)(x+1)}{(2x+1)(x+1)} x \frac{(2x-5)(2x-3)}{2x-3)(x-7)} x \frac{(2x+1)(2x-1)}{(2x-5)(2x+5)}
 
\frac{(x-7)(x+1)}{(2x+1)(x+1)} x \frac{(2x-5)(2x-3)}{(2x-3)(x-7)} x \frac{(2x+1)(2x-1)}{(2x-5)(2x+5)}
 
\frac{(2x-1)}{(2x+5)}
 
  • #10
\frac{5}{(x+3)} - \frac{(1)}{x-1}
 
  • #11
\frac{5}{(x+3)} - \frac{1}{x-1}
 
  • #12
\frac{5}{(x+3)} - \frac{(1)}{(x-1)}
\frac{5(x-1)}{(x+3)(x-1)} - \frac{(x+3))}{(x-1)(x+3)}
\frac{5(x-1)-(x+3)}{(x+3)(x-1)}
\frac{5x-5-x-3}{(x+3)(x-1)}
\frac{4x-8}{(x+3)(x-1)}
\frac{4(x-2)}{(x+3)(x-1)}
 
  • #13
Hollysmoke said:
\frac{x^2-6x-7}{2x^2+3x+1} x \frac{4x^2-16x+15}{2x^2-17x+21} / \frac{4x^2-20x+25}{4x^2-1}

Did you mean:
\frac{x^2-6x-7}{2x^2+3x+1} \times \frac{\frac{4x^2-16x+15}{2x^2-17x+21}}{\frac{4x^2-20x+25}{4x^2-1}}
 
Last edited:

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