yaseen shah
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i does not understand that in columbs constant where 4pi comes from
The factor of 4π in Coulomb's constant arises from the definition of the permittivity of free space (ε₀) in the context of Coulomb's law, expressed as F = 1/(4πε₀) * (q₁q₂/r²). This choice eliminates additional factors of 4π in Maxwell's equations, which are more frequently utilized in physics. In Gaussian units, the 4π is retained in Coulomb's law, highlighting the difference in unit systems. The geometrical interpretation of 4π relates to the area of a unit sphere and is essential for understanding Gauss's Law, where electric flux is proportional to the enclosed charge.
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It does. In fact you have the area of a sphere there, 4pi r^2. The constant epsilon0 is chosen so that the factor 4pi r^2 can be understood geometrically. There is nothing wrong with getting rid of the 4pi though, but the geometrical meaning is slightly less obvious.Good question. I have always assumed it corresponds to the unit sphere area of 4 pi steradians, but I could be wrong.