Where does the heat of super-nova end up after black hole formation?

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Khursed
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When a massive star dies, you either get a neutron star, or a black hole.

From my lecture, neutron star are extremely hot object, with temperature around 10E11 to 10E12 kelvin.

I'd assume black hole created from a similar process with just more mass, wouldn't have temperature any lower.

But I also read that black hole have temperature proportional to their size, which for solar sized one is measured in nano kelvin.

So my question is, how does a black hole get rid of its birthing creation temperature?
 
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It doesn't. All that happens is the associated energy cannot escape, so it contributes to the mass of the black hole.
 
Most of the energy of the supernova - including the case where a Neutrino star is remaining, is radiated away by photons and neutrinos. The remaining energy is either in the remnant's mass, heat, or rotational kinetic energy.
 
As said previously.. what you end up after a supernova are the SNR i.e supernova remnants the ingredients to the formation of heavier elements such as gold,etc. That's how we have got gold on our planet.

If my memory serves me right.. a flux of degenerate neutrons in a very short duration is radiated out, usually this would disintegrate but i think it forms heavier isotopes of different elements in a reaction called s-process.
 
Khursed said:
So my question is, how does a black hole get rid of its birthing creation temperature?

It swallows up all of the heat. Naively you'd expect a black hole to have a temperature of absolute zero since it eats up all of the energy falling into it. Where Stephen Hawking got his big start was to point out that this won't work without causing lots of heat problems, and so black holes have to have some small temperature.

If you put something really, really hot next to something really, really cold, you'd expect that energy to flow very quickly from the hot thing to the cold thing, which is what happens with a black hole.