Where is the Center of Gravity of a Lying Person?

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Homework Help Overview

The problem involves determining the center of gravity of a person lying on a board supported by two scales, with specific weight readings from each scale. The subject area pertains to mechanics, specifically the concepts of torque and center of mass.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using torque calculations about the center of mass to find the center of gravity. There are attempts to clarify the method of calculating torques from both sides and the choice of pivot point.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the torque calculations. Some guidance has been offered regarding the calculations, but there is no explicit consensus on the approach yet.

Contextual Notes

There are questions about the assumptions made regarding distances and the method of calculating torques, indicating potential confusion about the setup and parameters of the problem.

VanKwisH
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Homework Statement



A 160cm tall person lies on a light(massless) board which is supported by two scales , on under the feet and the beneath the top of the head. the scale under his feet read 29.4kg
and the scale under his head reads 32.8 kg ... where is the center of gravity of this person??

Homework Equations





The Attempt at a Solution

 
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What have you tried so far? It's always a good idea to start with a picture and a force-body diagram.
 
the simplest method to solve the problem is to calculate net torque abt the center of mass of person [take it as xi^+ yj^] from both the sides.then calculate the difference in the torques to get the value which gives the distance from the center of mass.

first proceed with the first step and update me of the progress.
 
huh ? i don't understand
 
what u mean is ... take the torques from each side ... and use the very middle of the person as the pivot point? am i correct ?
if so i got
t1 = 32.8 * 80
= 2624
t2=29.4 * 80
= 2352
does that look right??
 
comeon..how can you take the distance as 80 cm??

take it as .80m

the new relations are;

t1=.80*32.8
=26.24

t2=29.4*80=23.52
 
yah alright i get that ... next step??
 

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