Where is the point where the Earth's gravity is cancelled by the moon?

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SUMMARY

The discussion centers on calculating the point between the Earth and the Moon where gravitational forces cancel each other out. Given that the mass of the Moon is 1/81 that of the Earth, the gravitational force equations reveal that the cancellation point is located at a specific ratio of the distance to the Moon. The correct answer is determined to be 80/81 the way to the Moon, based on the gravitational force formula F=GMm/r^2 and the appropriate manipulation of variables.

PREREQUISITES
  • Understanding of gravitational force equations, specifically F=GMm/r^2
  • Basic knowledge of ratios and proportions
  • Familiarity with the concept of gravitational equilibrium
  • Ability to manipulate algebraic equations
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  • Study gravitational force calculations in detail using F=GMm/r^2
  • Explore the concept of gravitational equilibrium in multi-body systems
  • Learn about the mass and distance relationship in celestial mechanics
  • Investigate the Lagrange points and their significance in orbital mechanics
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Students in physics, astronomy enthusiasts, and anyone interested in gravitational interactions between celestial bodies.

chantelkohl
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Homework Statement


Somewhere between the Earth and the moon is a point where the gravitational attraction of the Earth is canceled by the gravitational pull of the moon. The mass of the moon is 1/81 that of the earth. How far away from the center of the Earth is this point?

a) 8/9 the way to the moon
b) 9/10 the way to the moon
c) 3/4 the way to the moon
d) 80/81 the way to the moon

Homework Equations


F=GMm/r^2


The Attempt at a Solution


GM/r^2=G(1/81)M/r^2-d
 
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I don't really get what that 'd' is doing hangen out there all by itself. If you look at your attempt, you need to have the 'r' on the other side denoted as something different, say for example r', where r' is the distance to the moon. What you're looking (in my opinion) is a ratio of the distances from the Earth to that certain point where the forces or equal and the distance from the moon. Start by multiplying both sides by [tex]r'^2[/tex] where r' is the distance to the moon.
 

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