Which child has the larger linear speed and acceleration on a Merry-go-round?

[lampshader]

Homework Statement

Two children ride on a Merry-go-round. One is 2 m from the axis of rotation and the other is 4m from it. Which child has the larger;

I. linear speed
II. acceleration
III. angular speed and
IV. angular displacement

Homework Equations

1) Linear Speed: v = ωr
2) Acceleration: a = F / m
3) Angular Speed = No. of radian/sec = ω = θ/t
4) Delta Theta = Theta(base1) - Theta(base0)

The Attempt at a Solution

I think I need to just pick one of the four, based on the information of the two children riding the mgr. Since child one is 2m from the axis of roation h/she is is traveling slower with a greater angular speed because the radius is smaller. The other, at 4m is traveling faster because the radius is greater than the other, in comparison.

Any other possibilities?

 

[ideasrule]

I think I need to just pick one of the four, based on the information of the two children riding the mgr. Since child one is 2m from the axis of roation h/she is is traveling slower with a greater angular speed because the radius is smaller.

This does not follow. A merry-go-round is a solid object. Why would the two people have different angular speeds?

 

[lampshader]

Its their linear speed. Because the further you are from the center, the higher velocity that you'll have.

 

[ideasrule]

Yes, they have different linear speeds, but the same angular speed.