Which lattice plane shows no diffraction peak in fcc crystal?

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    Crystallography
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SUMMARY

The discussion focuses on identifying the lattice plane in a face-centered cubic (fcc) crystal that exhibits no diffraction peak during X-ray diffraction (XRD). The planes considered include (2,1,2), (1,1,1), (2,0,0), and (3,1,1). It is established that the (2,1,2) plane does not produce a diffraction peak due to the systematic absence of reflections in fcc structures. The application of Bragg's law, nλ=2d sinθ, is essential for calculating the interplanar spacing and determining the hkl values from the XRD powder pattern.

PREREQUISITES
  • Understanding of face-centered cubic (fcc) crystal structures
  • Familiarity with X-ray diffraction (XRD) techniques
  • Knowledge of Bragg's law for diffraction analysis
  • Ability to calculate interplanar spacing (d) and Miller indices (hkl)
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  • Study the systematic absences in fcc crystal structures
  • Learn how to calculate Miller indices from XRD data
  • Explore the application of Bragg's law in X-ray diffraction
  • Investigate the interpretation of XRD powder patterns for crystal analysis
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Materials scientists, crystallographers, and researchers involved in X-ray diffraction analysis of crystalline materials will benefit from this discussion.

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Consider x ray diffraction from a crystal with an fcc(face centered cubic) lattice.
The lattice plane for which there is NO diffraction peak is -

1. (2,1,2)
2. (1,1,1)
3. (2,0,0)
4. (3,1,1)

I think Bragg's law must be used. nλ=2d sinλθ.
 
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can anyone tell me how to calculate hkl values and hence a,b,c values using xrd powder pattern
 

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