Which one of these statements is wrong ?

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Discussion Overview

The discussion revolves around identifying a potentially incorrect statement among five given statements related to linear algebra and vector spaces. Participants explore the validity of each statement, focusing on concepts such as matrix diagonalization, eigenvalues, and the properties of vector spaces.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Post 1 presents five statements and indicates that statements 1, 3, and 4 are considered correct by the poster, leaving statements 2 and 5 in question.
  • Post 2 suggests that statement 5 can also be ruled out but seeks clarification on the correctness of statement 2, providing an example of vectors in a specific form.
  • Post 3 asserts that since any linear combination of vectors in a vector space belongs to that space, statement 5 is correct.
  • Post 4 challenges statement 2, providing a counterexample of a 2x2 matrix that is not diagonalizable despite having distinct diagonal entries.
  • Post 5 reiterates the confusion regarding statement 2 and presents a similar example to Post 2, questioning the closure of a specific set under vector space operations.
  • Post 6 acknowledges the mistake in the example provided in Post 5, noting that the set described does not satisfy the properties of a vector space.

Areas of Agreement / Disagreement

Participants generally agree that statement 5 is correct, while there is contention regarding the validity of statement 2, with differing opinions on whether it is true or false.

Contextual Notes

Some participants' arguments depend on the definitions of vector spaces and the properties of diagonalizable matrices, which may not be universally agreed upon in this context.

Yankel
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Hello

I have a question in which I need to choose the wrong statement. I have 5 statements, and I managed to rule out 3 options so I am left with two.

the options are:

1. The dimension of the 3X3 anti-symmetric matrices subspace is 3.

2. An nXn matrix which has different numbers on it's main diagonal, is diagonalized.

3. A non invertible matrix has an eigenvalue of 0

4. Every matrix has a unique canonical form matrix

5. v1 and v2 are vectors from a vector space V. Then v1-2v2 also belongs to V.

I managed to rule out 1, 3 and 4 (they are correct in my opinion). I don't know which one is not, is it 2 or 5 ?
 
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I think I can rule out 5 too, but that doesn't help me understand why 2 is correct.

am I right to say:

let's assume that V is the space of all vectors of form (1,a,b), then:

v1 = (1,a,b) v2 = (1,c,d)

v1-2v2 = (-1,2-ac,b-2d) which doesn't belong to V ?
 
Hi Yankel!

If 2 vectors belong to a vector space, than any linear combination of those vectors also belongs to that vector space by definition.
Since $v_1-2v_2$ is a linear combination, (5) is correct.

As for (2), which values does a diagonal matrix have that are not on its main diagonal?
 
Yankel said:
2. An nXn matrix which has different numbers on it's main diagonal, is diagonalized.

This is false. Choose for example $A=\begin{bmatrix}{1}&{-2}\\{1}&{-1}\end{bmatrix}\in \mathbb{R}^{2\times 2}$. Its eigenvalues are $\lambda=\pm i\not\in \mathbb{R}$, so $A$ is not diagonalizable on $\mathbb{R}$.
 
Yankel said:
I think I can rule out 5 too, but that doesn't help me understand why 2 is correct.

am I right to say:

let's assume that V is the space of all vectors of form (1,a,b), then:

v1 = (1,a,b) v2 = (1,c,d)

v1-2v2 = (-1,2-ac,b-2d) which doesn't belong to V ?

As ILikeSerena told you, this is true. Your mistake is that the set $\{(1,a,b):a,b\in\mathbb{R}\}$ is not a vector space.
 
thank you both !

Yes, silly example, my set wasn't a vector space since it's not close on addition

(1+1!=1)

:eek:
 

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