Which point to sum the moments?

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theBEAST
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Homework Statement


Here is the problem:
Diagram of a crate on a platform mounted on two pivoting arms, with the platform rotating at angular speed ω about a radius r; labels mark points A, B, C, D, E, F, G, dimensions 0.5L, height H, and angle θ.


Here is the solution:
Handwritten solution sheet for a rigid crate problem showing acceleration expressions, a free-body diagram with forces mg, Ffc, Nc, Ffd and Nd, and force and moment equations (1) to (3), with equation (3) about point G circled in red.


I am confused about part c.


The Attempt at a Solution


Here is my attempt at part c:
Handwritten solution showing force and moment equations: sum Fx = -mu Nc - mu ND = m(-w^2 r cos theta), sum Fy = Nc + ND - mg = m(-w^2 r sin theta), sum Mc = -0.5Lmg + L ND = 0 so ND = 0.5mg, sum MD = 0.5Lmg - L Nc = 0 so Nc = 0.5mg.


I don't get why the answer key solution sums the moments about point G. I decided to sum up the moments about C and D and found out both normal forces are 0.5mg. However I quickly find out this is wrong because I am unable to solve the rest of the problem (which I did not include).
 
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If you take moments about D, say, you should not get a zero result. The crate's mass centre is accelerating to maintain its centripetal motion. This requires a moment about D. Taking moments about G avoids this.
 
What about [itex]ma_{x}[/itex] and [itex]ma_{y}[/itex] in your moment equation?

P.S. Sorry haruspex, I didn't see you already replied.