Who Has What? Solving Inequalities in Number Theory

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Homework Help Overview

The problem involves three individuals, Anna, Betty, and Carl, who collectively have $100. The discussion centers around formulating and solving inequalities based on their statements regarding the amounts of money they possess. This falls within the subject area of number theory and inequalities.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to set up equations based on the statements made by Anna and Betty. There is a focus on deriving relationships between the amounts of money each person has and exploring the implications of these relationships, particularly regarding integer values and constraints on Carl's amount.

Discussion Status

The discussion is ongoing, with participants actively working through the implications of the equations derived from the problem statements. Some guidance has been offered regarding the need to assume integer values for the amounts, and inequalities have been established to explore the possible values for Anna's amount.

Contextual Notes

There is an assumption that each individual has an integer amount of money, and Carl's amount is constrained to be less than $30. These constraints are critical to the exploration of potential solutions.

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Anna says, "We three have $100 altogether." Betty says, "Yes, and if you had six times as much and I had one-third as much, we three would still have $100." Carl says, It's not fair. I have less than $30." Who has what? (Dudley)
 
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This being a textbook problem, the question belongs in the Homework & Coursework forum.
 
Let A, B, C be the amounts of money Anna, Betty, and Carl have, respectively.

"We three have $100 altogether." A+ B+ C= 100

Betty (presumably responding to Anna) says, "if you had six times as much and I had one-third as much, we three would still have $100"
6 times as much for Anna would be 6A and one-third as much for Betty would be (1/3)B: 6A+ (1/3)B+ C= 100. Subtracting those two equations will eliminate C (Carl): (6-1)A+ (1/3- 1)B= 5A- 2/3 B= 0 or 2/3B= 5A so B= (15/2)A. Now, I think we will have to assume that each person has an integer number of dollars- in particular it follows from that that Anna has an even number of dollars. Use that equation, together with the fact that Carl has less than 30 dollars to see what integer amounts will satisfy the conditions.
 
Note that [tex]0\leq{C}=100-\frac{2}{2}A-\frac{15}{2}A=\frac{200-17A}{2}<30[/tex]
Thus, you have the inequality:
0<200-17A<60
 

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