Who Will Win In a Downhill Race?

  • Thread starter Thread starter physicStudent
  • Start date Start date
  • Tags Tags
    Race
Click For Summary
The discussion centers on determining which object will win a downhill race among various shapes, including a modified wooden disk, a metal sphere, and a cart with wheels. The modified disk is initially thought to have a lower coefficient of inertia, suggesting it would win, but the inclusion of the cart complicates the analysis. The cart's wheels rotate while the cart's body does not, requiring a different approach to derive its final velocity using conservation of energy principles. Participants are encouraged to consider how the number of wheels and the distribution of mass affect the cart's acceleration compared to the modified disk. The conversation emphasizes the importance of understanding the dynamics of both translational and rotational motion in solving the problem.
physicStudent
Messages
3
Reaction score
0

Homework Statement



Out of these various shapes: a wooden disk, a modified wooden disk with four pieces of metal in the middle, a smaller metal disk, a metal hoop, a small metal sphere, and a cart with four small wheels, who will win in a race rolling down a ramp with height h and angle Θ? An image of the cart is attached.

Homework Equations



v = \sqrt{\frac{2gh}{1+c}}, where c = coefficient of inertia

The Attempt at a Solution



We did an experiment in class where we were given the various shapes listed above (excluding the cart), and using the equation above, I found that the modified disk would win the race by thinking that the coefficient of its inertia must be smaller than that of the sphere (which came in second place with a coefficient of inertia of 2/5). However, I am stuck on this problem now with the inclusion of the cart. Any help is appreciated.
 

Attachments

  • Dynamic_cart.jpg
    Dynamic_cart.jpg
    21.1 KB · Views: 503
Physics news on Phys.org
When an object goes downhill it exchanges gravitatonal potential energy for other forms - including translational kinetic energy.

If the object rotates, then some of the energy gets stored in the rotation.

For most of your objects, the whole thing is rotating ... so the equation you have should work well.
For the cart, only the wheels are turning ... so you need to derive a different equation.
It has been included to see if you understand what you are doing instead of just plugging numbers into a potted solution.
 
So what would change in the conservation of energy equation to help in deriving this new equation? I assume that I would still be looking for the final velocity of the cart as it reaches the bottom of the ramp, but I'm not sure as to how to include the non-rotating portion of the cart into the equation. Also, would the number of wheels change the equation in any way?
 
Last edited:
You know that gravitational potential energy is traded for linear kinetic energy and rotational energy - start by writing out an expression that says that for the cart.
Which parts of the cart rotate? Which translate?
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
15K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
8K
  • · Replies 9 ·
Replies
9
Views
16K
Replies
2
Views
8K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
5
Views
7K