Who Will Win In a Downhill Race?

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SUMMARY

The discussion centers on determining which object will win a downhill race among various shapes, including a modified wooden disk, a metal sphere, and a cart with wheels. The key equation used is v = √(2gh/(1+c)), where c represents the coefficient of inertia. The modified disk is hypothesized to win due to its lower coefficient of inertia compared to the sphere. The inclusion of the cart introduces complexity, as only its wheels rotate, necessitating a different approach to derive its final velocity using energy conservation principles.

PREREQUISITES
  • Understanding of rotational dynamics and inertia coefficients
  • Familiarity with conservation of energy principles in physics
  • Knowledge of kinematic equations for rolling objects
  • Basic grasp of gravitational potential energy and its conversion to kinetic energy
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  • Derive the final velocity equation for a cart with rotating wheels
  • Explore the impact of different wheel counts on the cart's acceleration
  • Investigate the relationship between shape and coefficient of inertia for various objects
  • Learn about the dynamics of rolling motion and its equations
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Students studying physics, educators teaching mechanics, and anyone interested in the dynamics of rolling objects and energy conservation principles.

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Homework Statement



Out of these various shapes: a wooden disk, a modified wooden disk with four pieces of metal in the middle, a smaller metal disk, a metal hoop, a small metal sphere, and a cart with four small wheels, who will win in a race rolling down a ramp with height h and angle Θ? An image of the cart is attached.

Homework Equations



v = \sqrt{\frac{2gh}{1+c}}, where c = coefficient of inertia

The Attempt at a Solution



We did an experiment in class where we were given the various shapes listed above (excluding the cart), and using the equation above, I found that the modified disk would win the race by thinking that the coefficient of its inertia must be smaller than that of the sphere (which came in second place with a coefficient of inertia of 2/5). However, I am stuck on this problem now with the inclusion of the cart. Any help is appreciated.
 

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When an object goes downhill it exchanges gravitatonal potential energy for other forms - including translational kinetic energy.

If the object rotates, then some of the energy gets stored in the rotation.

For most of your objects, the whole thing is rotating ... so the equation you have should work well.
For the cart, only the wheels are turning ... so you need to derive a different equation.
It has been included to see if you understand what you are doing instead of just plugging numbers into a potted solution.
 
So what would change in the conservation of energy equation to help in deriving this new equation? I assume that I would still be looking for the final velocity of the cart as it reaches the bottom of the ramp, but I'm not sure as to how to include the non-rotating portion of the cart into the equation. Also, would the number of wheels change the equation in any way?
 
Last edited:
You know that gravitational potential energy is traded for linear kinetic energy and rotational energy - start by writing out an expression that says that for the cart.
Which parts of the cart rotate? Which translate?
 

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