Why add 3 instead of dividing by 3 in composite function

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Natasha1
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Homework Statement


Handwritten definition f(x) = 2x, where f of x equals 2 times x.
and
Handwritten line reading 3g(x) = x^2, where 3g(x) denotes three times g(x).


Find
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,
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and
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2. The attempt at a solution

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means work out
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, then work out
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for this value.

Equation fg(4) = f[g(4)] written in plain notation, showing the composite function notation for f of g of 4.


Handwritten line showing g(4) = 4^2 = 16.


so
Equation reading f[g(4)] = f(16), with f and g in italic and the brackets and parentheses as shown.


Handwritten line of working reading 2 x 16 + 3, with a minus-free expression showing the value 2 times 16 plus 3.


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I do not understand why we add + 3 in line before last (2 x 16 + 3)
Should it not be divided by 3 as it is
Handwritten line reading 3g(x) = x^2, with 3g(x) on the left and x squared on the right.
which means 3 x g(x) = x^2

I am a little stuck on the reason why?
 
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  • Handwritten definition f(x) = 2x, where f of x equals 2 times x.
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  • Handwritten line reading 3g(x) = x^2, where 3g(x) denotes three times g(x).
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  • Equation fg(4) = f[g(4)] written in plain notation, showing the composite function notation for f of g of 4.
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  • Handwritten line showing g(4) = 4^2 = 16.
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  • Equation reading f[g(4)] = f(16), with f and g in italic and the brackets and parentheses as shown.
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  • Handwritten line of working reading 2 x 16 + 3, with a minus-free expression showing the value 2 times 16 plus 3.
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  • Handwritten line reading 3g(x) = x^2, with 3g(x) on the left and x squared on the right.
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I'm not sure what they're doing with the ##+3## either but ##3g(x) = x^2## so ##g(x) = x^2/3## and ##g(4) = 16/3##, not 16. And ##f \circ g(4)## would be twice the value of ##g(4)##, definitely not 35.

Neither the calculation for ##g(4)## nor ##f[g(4)]## is consistent with the definitions you showed. Are you sure you have the right solution for the right question?
 
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I suggest a typo in the question. It should read f(x)=2x+3 g(x)=x2.
It would be most unusual to define g implicitly as 3g(x)=x2 instead of g(x)=x2/3.
 
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