Why Am I Getting Incorrect Solutions for My Quadratic Equation?

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Homework Help Overview

The discussion revolves around a quadratic equation and its application in a problem involving the volume of a hollow right cylinder derived from a solid sphere. The original poster presents a quadratic equation, x² - 8x + 4 = 0, and expresses confusion over obtaining incorrect solutions while attempting to solve it using the quadratic formula.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the quadratic formula but encounters issues with the arithmetic and the signs within the radical. Participants question the correctness of the formula used and the arithmetic steps taken.

Discussion Status

Some participants have pointed out potential errors in the application of the quadratic formula, specifically regarding the signs in the radical. The discussion is focused on identifying the mistakes in the calculations rather than reaching a consensus on the correct solution.

Contextual Notes

The original problem involves calculating the thickness of a hollow cylinder formed from a solid sphere, with specific dimensions provided. The expected answer is noted, but the original poster is struggling to arrive at this result.

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While solving an problem , i came to this quadratic
x2- 8x +4 =0
I couldn't break up 8x so i to solve it like this,
x= {-(-8)+√(8 2+ 4x1x4)}/2x1,{-(-8)-√(8 2+ 4x1x4)}/2x1
but the answers are coming way too absurd and negative.

The actual problem is:
"A hollow right cylinder of uniform thickness is made from the material obtained by melting a solid sphere of copper.If the diameter of the sphere is 12 cm,the height of the cylinder is 72 cm and the external radius of the base of the cylinder is 4 cm then find the thickness of the cylinder to two decimal places. "
And answer according to the book is 0.54 cm( which i am not getting !)


My doing any mistake in calculating or in the formulas?
Please help .I would be extremely grateful!
 
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It's just a silly little arithmetic mistake. The quadratic formula is
[tex] x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

You have pluses inside the radical in both cases.
 
Yes , i did that .
So what's wrong?
 
You were already told - you have plus inside the radical. Formula calls for minus.
 
Like I said, you have [tex]\sqrt{b^2 + 4ac}[/tex] instead of [tex]\sqrt{b^2 - 4ac}[/tex].
 

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