Why am I getting the wrong answer for the Fourier transform time-shift property?

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jaus tail
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Homework Statement


Two textbook problems: problem 17 gives X(w) = (1/w^2)(e^{jw} - jwe^{-jw} - 1) and asks for the Fourier transform of x(-t), with four multiple-choice options; problem 18 asks for the Fourier transform of x(-t-1), with four options.


Homework Equations


if x(t) --> X(W)
then
x(-t) --> X(-W)
and
x(t+a)-->ejwX(W)

The Attempt at a Solution


Handwritten working on lined paper: part (a) shows X(w) = -(1/w^2)(e^(jw) - jwe^(jw) - 1) and X(-w) = (1/w^2)(e^(-jw) + jwe^(-jw) - 1), marked correct; part (b) works x(-(t+1)) using time reversal and the time-shift property, ending with e^(-jw)(e^(jw) + jwe^(jw) - 1)/w^2, labelled answer B, with book answer C.

I'm getting right answer for 1st part. For second part book says right answer is C.
Where am I wrong?[/B]
 
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  • Two textbook problems: problem 17 gives X(w) = (1/w^2)(e^{jw} - jwe^{-jw} - 1) and asks for the Fourier transform of x(-t), with four multiple-choice options; problem 18 asks for the Fourier transform of x(-t-1), with four options.
    upload_2017-12-11_12-32-47.png
    6.9 KB · Views: 817
  • Handwritten working on lined paper: part (a) shows X(w) = -(1/w^2)(e^(jw) - jwe^(jw) - 1) and X(-w) = (1/w^2)(e^(-jw) + jwe^(-jw) - 1), marked correct; part (b) works x(-(t+1)) using time reversal and the time-shift property, ending with e^(-jw)(e^(jw) + jwe^(jw) - 1)/w^2, labelled answer B, with book answer C.
    upload_2017-12-11_12-33-14.png
    64.3 KB · Views: 867
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First you calculate x(t) by inverse Fourier tansform then by substituting t=-t and t=-t-1 you will get the result
 
So as per rules
if f(t)----> Fourier---> F(jw)
then f(t-to) ----> estoF(jw)
So then if there is now any more x(3(t-to)) then does the change reflect in esto also or is that a constant and only F(jw) becomes 1/|a| F(jw/a)?
 
This is what I tried for second part. But book answer is c
 
jaus tail said:
x(-t) --> X(-W)
jaus tail said:
So as per rules
if f(t)----> Fourier---> F(jw)
then f(t-to) ----> estoF(jw)
So then if there is now any more x(3(t-to)) then does the change reflect in esto also or is that a constant and only F(jw) becomes 1/|a| F(jw/a)?
jaus tail said:
So as per rules
if f(t)----> Fourier---> F(jw)
then f(t-to) ----> estoF(jw)
So then if there is now any more x(3(t-to)) then does the change reflect in esto also or is that a constant and only F(jw) becomes 1/|a| F(jw/a)?
Yes you can apply this property. i told you in previous post to recheck ur answer by that method.
 
Thanks. But I don't know how to use inverse Fourier method. What answer are you getting? B or C?
It could be book answer is wrong.

I wanted to ask a doubt on fourier?
If we have to use time shift property followed by time scaling property then does the exponential part also change?
Handwritten notes on lined paper deriving the Fourier transform of x(-(t+1)) using the time-delay and time-scaling properties, with the final exponential term circled and the question Will it be plus or minus? written beside it.

I can't find any solved examples. In laplace there were a few unsolved examples but then my answer matched when I didn't consider e^(-Ts) as part of new F(S). As in the second circle drawn above.
 
Attachments
  • Handwritten notes on lined paper deriving the Fourier transform of x(-t-1) using the time delay property followed by the time scaling property with a = -1, ending with e^(-jw) X(-w) or equivalent form.
    upload_2017-12-12_15-45-56.png
    53.8 KB · Views: 529
  • Handwritten notes on lined paper deriving the Fourier transform of x(-(t+1)) using the time-delay and time-scaling properties, with the final exponential term circled and the question Will it be plus or minus? written beside it.
    upload_2017-12-12_15-49-6.png
    64.5 KB · Views: 891
A
jaus tail said:
Thanks. But I don't know how to use inverse Fourier method. What answer are you getting? B or C?
It could be book answer is wrong.

I wanted to ask a doubt on fourier?
If we have to use time shift property followed by time scaling property then does the exponential part also change?
View attachment 216565
I can't find any solved examples. In laplace there were a few unsolved examples but then my answer matched when I didn't consider e^(-Ts) as part of new F(S). As in the second circle drawn above.
Just multiply by e^-jw to the answer you got in previous problem.In only time shift exponential term come you can do it by simple integration
 
That gives answer but should it be e^-jw or e^(+jw)
since x(-t-1) = x(-(t+1))
So I'm not sure how to go ahead with this. Should it be +jw or -jw?
 
jaus tail said:
That gives answer but should it be e^-jw or e^(+jw)
since x(-t-1) = x(-(t+1))
So I'm not sure how to go ahead with this. Should it be +jw or -jw?
-Jw
 
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In original post I've used time shift property first and then time scaling. Can u help me as to why I'm not getting right answer there? I've pasted pic.
 
jaus tail said:
In original post I've used time shift property first and then time scaling. Can u help me as to why I'm not getting right answer there? I've pasted pic.
You have done right but you choose option b and option b is not matching to you result may be in option c there is print mistake with minus sing in first term.
 
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