Fourier Transform Time Shifting Property

Click For Summary

Discussion Overview

The discussion revolves around the Fourier Transform (FT) time shifting property, specifically in the context of applying this property to a sine function with a time delay. Participants explore the mathematical manipulations involved and the implications of using different frequency variables in their calculations.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant describes their attempt to compute the FT of a sine function with a time delay, noting discrepancies in the results related to the variables 'f' and 'f0'.
  • Another participant references the property of the Dirac Delta function, suggesting it is relevant to the discussion of time shifting in Fourier Transforms.
  • A request for clarification on the application of the Dirac Delta function in the context of the participant's working out is made, indicating a need for deeper understanding.
  • Further inquiry is made about the implications of using the exponential function multiplied by the delta function, leading to a realization that the specific variable used may not affect the outcome due to the nature of the impulse function.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the application of the Dirac Delta function and its properties, with some reaching a consensus on the equivalence of results when using different frequency variables, while others seek further clarification.

Contextual Notes

There are unresolved aspects regarding the specific steps in the participant's calculations and how the Dirac Delta function is applied in their context. The discussion does not fully resolve the discrepancies noted in the initial attempts.

frenzal_dude
Messages
76
Reaction score
0

Homework Statement



I tried to work out the FT of a sin function with a time delay using first mathematical manipulation, and then using the time shifting property.

However I get two very similar, but for some reason not identical answers.

Homework Equations



Please open the .jpg to see my working out.
The answers are identical except for the 'f' and 'f0' which are circled in red pen.

The Attempt at a Solution



Thanks for your help!
 

Attachments

  • question2.jpg
    question2.jpg
    53.3 KB · Views: 612
Physics news on Phys.org
It follows from the fact that [itex]f(x)\delta(x-x_0) = f(x_0)\delta(x-x_0)[/itex].
 
vela said:
It follows from the fact that [itex]f(x)\delta(x-x_0) = f(x_0)\delta(x-x_0)[/itex].

could you please explain further?
 
frenzal_dude said:
could you please explain further?
Are you familiar with the Dirac Delta function and its properties?
 
Hootenanny said:
Are you familiar with the Dirac Delta function and its properties?

Yeh I am. And I understand the equation given. But where is that happening in my working out?

The exponential with f0 and t0 given is simply a complex number, and can't be considered a dirac delta function in the frequency domain right?
 
What do you get if you apply that property to, say, [itex]e^{j2\pi f t_0} \delta(f-f_0)[/itex] (where [itex]e^{j2\pi f t_0}[/itex] is the function multiplying the delta function)?
 
vela said:
What do you get if you apply that property to, say, [itex]e^{j2\pi f t_0} \delta(f-f_0)[/itex] (where [itex]e^{j2\pi f t_0}[/itex] is the function multiplying the delta function)?

I fully get it now!

Basically it doesn't matter if you use f or f0, the result is the same since you are multiplying with an impulse at f=f0!

Thanks so much for your help!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
8
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K