Why Are All Coefficients Zero in My Fourier Series Calculation of Sin(2x)?

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Homework Help Overview

The discussion revolves around the calculation of the Fourier series for the function f(x) = sin(2x), with participants expressing concerns about obtaining zero coefficients for a0, an, and bn.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are examining the implications of using different basis functions and intervals for the Fourier series. There is a discussion about the nature of sine functions and their coefficients, particularly questioning why all coefficients might be zero.

Discussion Status

Some participants have provided insights regarding the properties of sine functions and the expected behavior of coefficients, suggesting that not all coefficients should be zero. There is an ongoing exploration of the calculations involved.

Contextual Notes

Participants are considering the implications of odd functions on the coefficients and the specific basis functions being used, indicating potential misunderstandings in the setup of the Fourier series calculation.

Zeitblom
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I have to find the Fourier series of f(x)=sin(2x)
but i always get all the coefficients (a0, an and bn) equal zero.
is it right?
Thank you
 
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It depends on what basis functions and interval you use. If the often used basis {1,cos(x),cos(2x),...,sin(x),sin(2x),...} with interval length 2pi the answer should be obvious.
 
sin is an odd function, so half your coefficients should be zero, not all of them
 
Zeitblom said:
I have to find the Fourier series of f(x)=sin(2x)
but i always get all the coefficients (a0, an and bn) equal zero.
is it right?
Thank you

Did you check b_2 carefully? It shouldn't be 0.
 

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