Why are specific enthalpies equal in this heat transfer problem?

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strider171
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Homework Statement



Physics problem diagram: right isosceles triangle ABC with a right angle at B, A marked T at top, B marked sqrt(2)T, C at the right, with a 90 degree angle label; answer choices (a) T/(sqrt2 - 1), (b) T/(sqrt2 + 1), (c) 3T/(sqrt2 + 1), (d) T/(sqrt3(sqrt2 - 1)).

Homework Equations


Handwritten solution to problem 5: a right triangle with corners A, B and C, heat flows H1 from B to C and H2 from C to A, temperatures T and √2T marked, then H1 = H2 and the equation (√2T − Tc)/(l/KA) = (Tc − T)/(√2l/KA) leading to Tc = 3T/(√2 + 1).


The Attempt at a Solution


This is a solved question. The answer is given above.
I can't understand why h1=h2.
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Assume that ##T_C## is between ##T_A## and ##T_B## and that there are equal heat flow rates ##B \rightarrow C## and ##C \rightarrow A## (because we want to calculate steady-state temperatures, and without the equality of the rates the ##T_C## would be changing).
 
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strider171 said:
I can't understand why h1=h2.

H = heat flow. Heat H1 flows down B->C. The problem says to assume only conduction (eg through the rods) no radiated losses so where else can that heat flow go if not down C->A ? Therefore H1=H2.
 
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