Why are the potentials the same?

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Homework Help Overview

The discussion revolves around understanding why the electric potentials across two capacitors are the same in a given circuit configuration. The subject area pertains to circuit theory, specifically focusing on capacitors and their arrangement.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster seeks justification for the equality of potentials, expressing a need for a theoretical explanation. Some participants assert that the capacitors are connected in parallel, which leads to the same potential across them. However, another participant questions the parallel connection, suggesting a possible series arrangement instead.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the circuit configuration. Some guidance has been offered regarding the parallel connection, but there is no explicit consensus on the arrangement of the capacitors.

Contextual Notes

Participants are navigating assumptions about the circuit layout, particularly regarding the connections between the capacitors and the implications for potential equality. There is an indication of differing views on whether the capacitors are in series or parallel.

s3a
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Could someone tell me why the potentials are the same in http://i.imgur.com/EdnqE.jpg.

I am talking about right under the part where it says "Also, the potentials across them are now the same, so that V = q/C gives". I understand everything prior to that. I even understand the stuff after it! I just need to justify to myself the theory behind why the potentials are equal so that I can move on. Please be elaborate but a short response is fine.

Any input would be greatly appreciated!
Thanks in advance!
 
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They are connected in parallel so the potential is the same for both.
 
How do you discern that they are parallel? I was under the impression that "(b) After" is in series.
 
The positive terminal is connected to the positive terminal in both capacitors.
 

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