Why can positron go unobstructed through lead?

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Positrons can traverse a 6mm lead plate due to the pair-production mechanism, where high-energy gamma rays interact with lead nuclei, resulting in the creation of electron-positron pairs. This phenomenon was explored in Anderson's positron experiment, which involved discussions with physicists like Robert Oppenheimer. Unlike the gold foil experiments that utilized very thin sheets, the lead plate's thickness does not prevent positron generation within the material when subjected to high-energy radiation.

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Can anyone explain why a positron, in a charged magnetic field, is able to go through a 6mm lead plate, as seen in Anderson's positron experiment?

Initially I thought that it could be quite similar to the gold foil experiments, but one of the features of the gold foil experiments is that it is using a VERY thin sheet of gold.

From what I understand lead, especially lead that thick, has the ability to not easily allow particles through.

Am I taking the wrong approach?

http://en.wikipedia.org/wiki/File:PositronDiscovery.jpg
 
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In trying to understand the results of his experiments, Anderson consulted several other prominent physicists, including Robert Oppenheimer. Anderson's discussions with Oppenheimer proved fruitless; however, other physicists were studying cosmic rays like Anderson at this time. Two of them, P.M.S. Blackett and G.P.S. Occhialini, proposed the pair-production mechanism, where high-energy photons, like the gamma rays found in cosmic radiation, will strike a nucleus and produce an electron-positron pair. These particles will annihilate one another after a brief period, turning back into two gamma rays.

It's not that positrons penetrate lead, but positrons are produced within the plate when high-energy gamma rays strike one of the lead nuclei.

For details on the pair-production mechanism, see this article:
http://en.wikipedia.org/wiki/Pair_production
 

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