Why Can't Neutron Emission Occur in K(40,19) Decay?

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Homework Help Overview

The discussion centers on the decay modes of potassium-40 (K(40,19)), specifically addressing why neutron emission is not a feasible decay pathway for this isotope.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the neutron to proton ratio as a factor in decay stability and question the energy requirements for neutron emission. There is a focus on the mass of the resulting nucleus and the Q value of the decay process.

Discussion Status

Some participants have provided insights regarding the energy considerations of neutron emission, noting the negative Q value as a critical factor. There seems to be an ongoing exploration of the implications of these findings without a definitive consensus.

Contextual Notes

Participants are considering the stability of K(40,19) in terms of its neutron to proton ratio and the energy dynamics involved in potential decay pathways.

Amith2006
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Homework Statement


1)Neutron emission is not a possible mode of decay for K(40,19).Why?


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The Attempt at a Solution



I think it is because the neutron to proton ratio for potassium(40,19) is almost unity(more precisely N/P=1.1). So, neutron emission is not a mode of decay to gain stability. Is it right?
 
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No. You have to look at the nucleus it would decay to, and compare masses.
 
Meir Achuz said:
No. You have to look at the nucleus it would decay to, and compare masses.

I found the Q value of the reaction and obtained a negative value(-7.8 MeV).
K(40,19)---> K(39,19) + neutron
So, it doesn't have sufficient energy for neutron emission to take place. Is that what u meant?
 
Yes...
 
Cool!Thanx mate.
 

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