Why Can't We See Diffraction from Metal Surfaces?

Click For Summary
Metal surfaces do not exhibit visible diffraction patterns due to their atomic structure and the presence of free electrons, which create a barrier that prevents light waves from interacting with the atomic grating. The complex refractive index of metals, with its imaginary component, accounts for the absorption and reflection of electromagnetic waves, further obscuring diffraction effects. In contrast, dielectrics, which lack free electrons, can show diffraction patterns since their atomic spacing is suitable for visible wavelengths. However, X-rays and gamma rays can penetrate metal surfaces and interact with the atomic structure, allowing for diffraction to occur in these cases. Thus, while visible light cannot diffract off metals, higher energy electromagnetic radiation can reveal their crystalline properties.
brianeyes88677
Messages
14
Reaction score
0
The atoms in a metal (ex. Cu) are arranged as a 3-D grating. But to our common sense ,smooth metal surfaces only reflect lights. Why can't we see diffraction from metal surfaces?
 
Physics news on Phys.org
The metals contain a see of free electrons. In EM we know refractive index for metals is complex. Imaginary part of n is responsible for absorption and reflection of EM waves. This sea is like a cover which is in surface of metals. Therefore the wave cannot see grating.

Why can't we see diffraction pattern from crystals without see of free electrons like dielectrics?

Since from formula of diffraction sin(Teta)=i*landa/d must d>landa( <=> sin(Teta)<1) and in crystal the d(distance between two atoms) is about angstrom therefore there is no diffraction pattern for ultraviolet up to radio waves. for example we don't see light diffraction from glasses.

X-ray and gamma have diffraction through crystals and X-ray is one of must important instrument in crystallographic.
Also in metals we have X-ray diffraction. Gamma and X-ray can pass from surface and see grating. This lead to have diffraction from metals.

I apologize for scribbling English. My language isn't English but i am trying to improve it.
 
I make mistake in above,difference of real part of n and the environment refractive index is responsible of reflection.
 
abbas_majidi said:
The metals contain a see of free electrons. In EM we know refractive index for metals is complex. Imaginary part of n is responsible for absorption and reflection of EM waves.

What do you mean for "imaginary part of n is responsible for absorption and reflection of EM waves" ?
My native language isn't English too.
 
In Electromagnetic theory refractive index of metals(n) obtain as complex number and imaginary part of n arises from absorption of EM waves by metals. In other word complex n is Representative of absorption in matter.
 
I'm setting up an analog power supply. I have the transformer bridge and filter capacitors so far. The transformer puts out 30 volts. I am currently using two parallel power transistors and a variable resistor to set the output. It also has a meter to monitor voltage. The question is this. How do I set up a single transistor to remove whats left of the ripple after the filter capacitors. It has to vary along with the control transistors to be constant in its ripple removing. The bases of the...

Similar threads

  • · Replies 3 ·
Replies
3
Views
896
Replies
7
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
6
Views
3K
Replies
6
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K