Why do different formulae give me different answers for mass of galaxy?

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SUMMARY

The discussion focuses on calculating the mass of the Milky Way galaxy using different methods, specifically Newton's laws and Kepler's Third Law. Three calculations yield different mass estimates: 1.7 x 1041 kg, 7.1 x 1010 Mʘ (equivalent to 1.4 x 1041 kg), and 1.3 x 1041 kg. The discrepancies arise from variations in the radial velocity of the sun and the orbital period used in the calculations. Understanding these differences is crucial for accurate astrophysical modeling.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with Kepler's laws of planetary motion
  • Knowledge of gravitational constant (G = 6.67 x 10-11 Nm2kg-2)
  • Basic concepts of circular motion and centripetal force
NEXT STEPS
  • Study the derivation and applications of Newton's form of Kepler's Third Law
  • Learn about the implications of radial velocity in celestial mechanics
  • Research methods for estimating galactic mass using different astronomical techniques
  • Explore the significance of significant figures in scientific calculations
USEFUL FOR

Astronomy students, astrophysicists, and anyone involved in celestial mechanics or galactic dynamics will benefit from this discussion.

anyaxo
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I am trying to calculate the mass of the galaxy within the orbit of the sun.

M = Mass of the galaxy = ?
r = ‘Distance of sun from galactic centre = 7.6 kpc’ = 2.3 x 1017 km = 2.3 x 1020 m (2 sf)
G = Gravitational constant = 6.67 x 10-11 Nm2kg-2
v = ‘Radial velocity of the sun = 220,000 ms-2’

Since the Sun’s orbit around the galactic centre is nearly circular, it undergoes circular motion and experiences a centripetal force:

〖mv〗^2/r = - GMm/r^2

v^2 = GM/r
M= ((220,000)^2 (2.3 ×〖10〗^20))/(6.67 ×〖10〗^(-11) )
=1.7 × 〖10〗^41 kg (2 significant figures)
Using Newton's form of Kepler's Third Law..

r = ‘distance of sun from galactic centre = 1.6 x 109 AU (Astronomical Units)’ 13
T = ‘orbital period of the sun = 2.4 x 108 Julian Years’
M = Mass of galaxy = ?

M= r^3/T^2

M= 〖(1.6 × 〖10〗^9)〗^3/〖(2.4 ×〖10〗^8)〗^2

M=7.1 × 〖10〗^10 M_ʘ

This proves that if every star has approximately the mass of the sun, there are approximately 7.1 x 10^10 stars in the Milky Way.

7.1 x 10^10 Mʘ = 1.4 x 10^41 kg (2 significant figures)

Finally, by using the original form of Kepler’s Third Law we can also obtain the mass of a galaxy.

T = ‘orbital period of the sun = 2.4 x 108 Julian Years’ 15 = 7.57 x 1015 seconds
r = ‘distance of sun from galactic centre = 2.3 x 1017 km’ 13= 2.3 x 1020 m
G = Gravitational constant = 6.67 x 10-11 Nm2kg-2

T^2=(〖4π〗^2/GM)r^3

M= (4π^2 r^3)/(GT^2 )

M= (4 × π^2 ×〖(2.3 × 〖10〗^20)〗^3)/((6.67 × 〖10〗^(-11) ) 〖(7.57 × 〖10〗^15)〗^2 )

M = 1.3 x 10^41 kg (2 significant figures)

Why are my three answers (all in bold) so different? and which one is correct and why? I need to explain this for my coursework!
 
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Using your values for R and T, I get v = 2πr/T = 1.91 x 10^5 m/s, which is not the same as the 220,000 m/s you use in the first calc.
 

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