Why do Eu doped phosphors show fluorescence property without singlet?

In summary, the discussion revolves around the luminescence properties of trivalent Eu doped phosphor material and the confusion between fluorescence, phosphorescence, and down-conversion processes. The expert explains that the strong spin-orbit coupling of lanthanides makes it difficult to categorize their luminescence as either fluorescence or phosphorescence, and suggests using the term "luminescence" instead. The expert also clarifies that the 5D0 --> 7FJ transition, which is commonly associated with fluorescence, actually has a slow radiative rate. The conversation also touches on the expert's qualifications and how they can tailor their answer to the questioner's level of knowledge on the subject.
  • #1
pallab
36
3
As it is mentioned fluorescence is a singlet to singlet transition and this is the reason that fluorescence is a fast process. now consider the Eu doped phosphor material where 5D0--->7F2 and other transitions show the prominent intensity peaks in down-conversion process. those are not singlet to singlet transition but yet Eu doped phosphor material shows fluorescence. Why?
 
Physics news on Phys.org
  • #2
There are some multiple stages of misunderstanding you have, which makes it hard for me to know where to start.

No, trivalent Eu (which is what I am assuming you are talking about, not divalent) does not show "fluorescence".

But it's kinda hard to say of lanthanide transition as "fluorescence" or "phosporescence". First of all, spin-orbit coupling of lanthanides are fairly strong, so the "spin-ness" and "orbital-ness" is muddled here since they are mixed. As such is not really easy to say fluorescence (transition between same spin states) or phosphorescence (transition between different spin states) in lanthanides. I generally say just "luminescence". I have seen reports saying "phosphorescence", but I have never seen anyone say of lanthanide luminescence as "fluorescence".

Also, I don't like how you use the word "down-conversion". In a broad sense, almost all luminescence is a down-conversion, but most people use the term when multiple emission occurs (e.g. sequential emission, quantum cutting).

Trivalent lanthanides primarily show luminescence based on 4f-4f transition. This is a Laporte forbidden transition, so it's not a fast process at all. 5D0 --> 7FJ transition in total only has radiative rate constant of around 400 - 1000 s-1. To say that is fast is a massive understatement considering fluorescence has somewhere around 109 s-1.
 
  • Like
Likes pallab and dRic2
  • #3
HAYAO said:
There are some multiple stages of misunderstanding you have, which makes it hard for me to know where to start.

No, trivalent Eu (which is what I am assuming you are talking about, not divalent) does not show "fluorescence".

But it's kinda hard to say of lanthanide transition as "fluorescence" or "phosporescence". First of all, spin-orbit coupling of lanthanides are fairly strong, so the "spin-ness" and "orbital-ness" is muddled here since they are mixed. As such is not really easy to say fluorescence (transition between same spin states) or phosphorescence (transition between different spin states) in lanthanides. I generally say just "luminescence". I have seen reports saying "phosphorescence", but I have never seen anyone say of lanthanide luminescence as "fluorescence".

Also, I don't like how you use the word "down-conversion". In a broad sense, almost all luminescence is a down-conversion, but most people use the term when multiple emission occurs (e.g. sequential emission, quantum cutting).

Trivalent lanthanides primarily show luminescence based on 4f-4f transition. This is a Laporte forbidden transition, so it's not a fast process at all. 5D0 --> 7FJ transition in total only has radiative rate constant of around 400 - 1000 s-1. To say that is fast is a massive understatement considering fluorescence has somewhere around 109 s-1.
Thanks for your reply
 
  • #4
HAYAO said:
There are some multiple stages of misunderstanding you have, which makes it hard for me to know where to start.

No, trivalent Eu (which is what I am assuming you are talking about, not divalent) does not show "fluorescence".

But it's kinda hard to say of lanthanide transition as "fluorescence" or "phosporescence". First of all, spin-orbit coupling of lanthanides are fairly strong, so the "spin-ness" and "orbital-ness" is muddled here since they are mixed. As such is not really easy to say fluorescence (transition between same spin states) or phosphorescence (transition between different spin states) in lanthanides. I generally say just "luminescence". I have seen reports saying "phosphorescence", but I have never seen anyone say of lanthanide luminescence as "fluorescence".

Also, I don't like how you use the word "down-conversion". In a broad sense, almost all luminescence is a down-conversion, but most people use the term when multiple emission occurs (e.g. sequential emission, quantum cutting).

Trivalent lanthanides primarily show luminescence based on 4f-4f transition. This is a Laporte forbidden transition, so it's not a fast process at all. 5D0 --> 7FJ transition in total only has radiative rate constant of around 400 - 1000 s-1. To say that is fast is a massive understatement considering fluorescence has somewhere around 109 s-1.
I have seen that Eu3+/Yb3+ doped phosphor emitting reddish light while excited with NIR laser. and it stopped emission immediately the laser turned off. So my thought was that it is a fluorescence. though for the 5D0--->7F2 transition it was excited with UV light, not with NIR laser. then I studied the singlet state-triplet state involvement and the question arose which has been posted.
 
  • #5
What did you major in college and what is your major now? It will help me write an answer that best suits your level of knowledge on this subject.
 
  • #6
HAYAO said:
What did you major in college and what is your major now? It will help me write an answer that best suits your level of knowledge on this subject.
physics
 
  • #7
pallab said:
physics
Could you be more specific? You are doing your masters as far as I can see from your profile. You are in a graduate school, which means you are in a lab. What is your research area? It sounds like you are clearly clueless about luminescence so much that you don't seem to understand my answer. I want to know your background so that I can write an answer that you can comprehend.
pallab said:
I have seen that Eu3+/Yb3+ doped phosphor emitting reddish light while excited with NIR laser. and it stopped emission immediately the laser turned off. So my thought was that it is a fluorescence. though for the 5D0--->7F2 transition it was excited with UV light, not with NIR laser. then I studied the singlet state-triplet state involvement and the question arose which has been posted.

This is wrong in so many different stages. What is the typical emission lifetime of 5D0 state? A quick search will get you the answer (and my previous answer should've answer it as well), and that will answer why "emission stopped immediately", and no, that's not how we identify fluorescence and phosphorescence. Also, excitation with NIR laser means you attempted upconversion, while as for UV light you most likely excited the charge transfer band of Eu3+ (unless you use a laser, you usually can't visibly see an emission because of the small absorption cross-section of 4f-4f transition, so you instead excited the CT band. This is the principle of red portion of emission of the fluorescent lamps). Also, how is singlet and triplet involved here? 5D0 is quintet in purely LS terms and 7FJs are septet. And even that is irrelevant to lanthanides because of spin-orbit coupling.
 
Last edited:
  • #8
HAYAO said:
Could you be more specific? You are doing your masters as far as I can see from your profile. You are in a graduate school, which means you are in a lab. What is your research area? It sounds like you are clearly clueless about luminescence so much that you don't seem to understand my answer. I want to know your background so that I can write an answer that you can comprehend.

This is wrong in so many different stages. What is the typical emission lifetime of 5D0 state? A quick search will get you the answer (and my previous answer should've answer it as well), and that will answer why "emission stopped immediately", and no, that's not how we identify fluorescence and phosphorescence. Also, excitation with NIR laser means you attempted upconversion, while as for UV light you most likely excited the charge transfer band of Eu3+ (unless you use a laser, you usually can't visibly see an emission because of the small absorption cross-section of 4f-4f transition, so you instead excited the CT band. This is the principle of red portion of emission of the fluorescent lamps). Also, how is singlet and triplet involved here? 5D0 is quintet in purely LS terms and 7FJs are septet. And even that is irrelevant to lanthanides because of spin-orbit coupling.
Project: spectroscopic studies on Eu3+/Yb3+ doped Y2O3 phosphors
Yes, I am clueless but I am trying to fathom out the physics behind this luminescence.
what I was considering as true for this luminescence, faced a challenge to the result of UV light excitation
 
  • #9
pallab said:
Project: spectroscopic studies on Eu3+/Yb3+ doped Y2O3 phosphors
Yes, I am clueless but I am trying to fathom out the physics behind this luminescence.
what I was considering as true for this luminescence, faced a challenge to the result of UV light excitation
Y2O3. I see, so you are working on one of the most common lanthanide-based phosphors. They are used in fluorescent lamps by doping Eu3+ (red), Tb3+(green), and Ce3+(blue) to produce white light. These lanthanide ions absorb in the UV region by CTS band (Eu3+) and 4f5d band (Tb3+ and Ce3+). The emission is 5D0 --> 7F2 (Eu3+ red) and 5D4 --> 7F5 (Tb3+ green). But Ce3+ is an exception since its blue emission is also 4f5d transition (also, it's fluorescence unlike Eu3+ and Tb3+).

Human eyes only have detection frequency up to 60 frames per second, under the circumstances that you are looking at a flashing light source. That means no less than 16.7 millisecond of light intensity changes can be detected by the human eye (and even longer if you are talking about one single pulse of light). Emission lifetime of Eu3+ ( 5D0 --> 7FJ transition ) in Y2O3 is somewhere around 1 - 3 ms (depending on how they are prepared). So if you turn off the excitation light, the emission of Eu3+ appears to human eye as if it instantaneously stops. In another words, you can't tell the difference between fluorescence and phosphorescence by human eyes (there are some minor exceptions where some organic phosphors show phosphorescence lifetime of over few seconds).

If you are working on Eu3+/Yb3+, my speculation is that you are working on its upconversion properties. By using NIR laser, you are exciting multiple Yb3+ ions in hope that some of them are going to sequentially transfer its energy to Eu3+ ion, and exciting it to higher energy level so that it will emit. Basically, you are converting NIR light (lower energy) into visible light (higher energy), hence the term "upconversion".

There are literally hundreds and thousands of upconversion articles out there, and even more about spectroscopic properties of Eu3+ and Yb3+ ions. Their quantum mechanical spectroscopic theory was developed by Judd (Phys. Rev. 1962) and Ofelt (J. Chem. Phys. 1962) separately, and they are widely known as the Judd-Ofelt theory. No one working on the optical properties of rare-Earth's should be oblivious to the existence of this theory, so I highly suggest you read them. A less technical but well summarized article of the theory is available by Hehlen (J. Lumin. 2013).

You also might want to check out textbooks for basic spectroscopy and photoluminescence. Also, you should grab an inorganic chemistry textbook and condensed matter physics textbook that covers crystal field theory. Crystal field theory is crucial in understanding lanthanide luminescence, and will also help you understand the Judd-Ofelt theory since that's what the theory bases itself on. Also, Judd-Ofelt theory is a semi-empirical quantum mechanical theory based on spherical tensor techniques. Therefore, you should also refer to any textbook that concerns atomic spectra. Since you are a physics major, a strong quantum mechanics background will greatly help you in understanding them.

Good luck.
 
  • Like
Likes pallab

1. Why do Eu doped phosphors show fluorescence property without singlet?

Europium (Eu) is a rare earth element that is commonly used as a dopant in phosphors. When Eu is added to a phosphor material, it creates a defect in the crystal lattice structure, which allows for energy transfer between the Eu ions and the host material. This energy transfer results in the emission of light, or fluorescence, without the formation of singlet states.

2. What is the role of Eu in the fluorescence property of phosphors?

The role of Eu in the fluorescence property of phosphors is to act as a dopant, or impurity, in the host material. The presence of Eu ions creates a defect in the crystal lattice structure, which allows for energy transfer between the Eu ions and the host material. This energy transfer results in the emission of light, or fluorescence, without the formation of singlet states.

3. How does the presence of Eu affect the fluorescence efficiency of phosphors?

The presence of Eu can greatly enhance the fluorescence efficiency of phosphors. This is because the energy transfer between the Eu ions and the host material can increase the number of photons emitted, resulting in a brighter and more efficient fluorescence. Additionally, the unique electronic structure of Eu allows for efficient energy transfer and emission of light.

4. Are there other dopants besides Eu that can produce fluorescence in phosphors?

Yes, there are many other dopants that can produce fluorescence in phosphors. Some common examples include rare earth elements such as terbium, neodymium, and dysprosium. These dopants also create defects in the crystal lattice structure, allowing for energy transfer and emission of light.

5. Can the fluorescence property of Eu doped phosphors be controlled?

Yes, the fluorescence property of Eu doped phosphors can be controlled by adjusting the concentration of Eu ions, as well as the composition and structure of the host material. This can affect the energy transfer and emission processes, resulting in different fluorescence properties such as color and intensity.

Similar threads

  • Computing and Technology
Replies
25
Views
3K
Replies
2
Views
9K
Replies
11
Views
2K
  • Quantum Interpretations and Foundations
Replies
21
Views
2K
  • Quantum Interpretations and Foundations
Replies
3
Views
972
Replies
13
Views
2K
  • Beyond the Standard Models
Replies
11
Views
2K
  • Other Physics Topics
Replies
0
Views
728
Replies
3
Views
977
  • Beyond the Standard Models
Replies
14
Views
3K
Back
Top