Why do fermions have 1/2-integer spins?

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Fermions possess half-integer spins and follow Fermi-Dirac statistics due to their antisymmetric wavefunctions, while bosons have whole integer spins and obey Bose-Einstein statistics. The connection between half-integer spin and antisymmetric wavefunctions is rooted in the spin-statistics theorem, which is a fundamental principle in quantum field theory (QFT). This theorem establishes that the nature of particle spin is intrinsically linked to the statistical behavior of particles. For a deeper understanding, references such as the Wikipedia page on the spin-statistics theorem and detailed QFT notes are suggested. Understanding these concepts is essential for grasping the underlying principles of particle physics.
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Hello,

Could anyone explain why fermions have half-integer spins and obey the fermi-dirac statics, whereas bosons have whole integer spins and don't? I have read lots of explanations at a fairly basic level for this, which say that this happens because fermions have antisymmetric wavefunctions. However, they do not fully explain the connection between 1/2-integer spin and antisymmetric wavefunctions. I've heard vaguely that there is an explanation for this in QFT (ie, spin and statistics are not just intrinsic properties that cannot be explained from other principles)... So could anyone explain or point me to a reference as to what the actual explanation IS?

Thanks!
 
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The result is known as the spin-statistics theorem. There's a proof on that wiki that is a bit short of details. There is a much more detailed proof explained in these notes that might be a better read, though in either case basic familiarity with QFT is assumed.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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