Why Do My Momentum Problem Solutions Differ from the Textbook Answers?

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SUMMARY

The discussion focuses on discrepancies between calculated forces in two physics problems involving momentum and collisions. In the first problem, the user calculates an average force of approximately 2808 N on a roof from falling hailstones, while the textbook states the answer is 1900 N. The user identifies that neglecting the gravity term yields a closer approximation of 1885 N. In the second problem, the user struggles to derive the force exerted on the ground by a dropped ball, ultimately noting that the textbook answer is simply mg, indicating a focus on terminal velocity.

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neelakash
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I did the following two questions of the same category.But the answer is not matching.Please see if I went wrong.

Homework Statement



1.During rainfall,2000 hailstones per square metre (radius 0.5 cm) falls onto a 10mx10x roof with velocity 20m/s.FInd the average force exerted onto the roof without rebound.Density of hailstones 900kg/m3

2.A ball of mass m is dropped onto the ground from a certain height.Colliding elastcally,it again rises to that height.Again it falls.What is the force exerted onto the grond in a long interval of time?

Homework Equations



I think in both cases we may use this standard equation:
P=F_ext+u(dM/dt) where u is the relative velocity

The Attempt at a Solution



(1) In problem (1),the total mass is 30*pi.You may check it.
So,total force exerted on the roof
F=F_floor+F_gravity
Taking magnitudes---
=u(dM/dt)+Mg
=20*30*pi+30*pi*g (where g is the acceleration due to gravty).
~2808N
whereas the book says it is 1900 N
I noted that if we neglect the gravity term,the answer (1885N) is close to 1900N

(2)Here what I got is

F=F_floor+F_gravity
Taking magnitudes,-
=u(dm/dt)+mg
=d(mu/dt)+mg
since the u has not been giveen,I could not proceed more.
However,they have provided the answer mg.
 
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OK,first part is clear.They referred to terminal velocity.Hence,the term "average".So,F_ext=0
 

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