Why do textbooks have conflicting answers about the hybrid orbitals in H2S?

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Discussion Overview

The discussion revolves around the conflicting answers found in textbooks regarding the hybridization of orbitals in H2S. Participants explore the nature of hybridization, its applicability, and how it relates to molecular geometry and bond angles.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Technical explanation

Main Points Raised

  • Some participants predict that H2S forms sp3 hybrid orbitals, yet note that its bond angles deviate from the expected 109.5 degrees.
  • Others argue that hybridization is not binary and suggest that H2S may exhibit partial hybridization, leading to non-equivalent bonds.
  • One participant emphasizes that hybridization is a choice for expressing a molecule's wavefunction, suggesting that H2S may be better described using pure s and p orbitals rather than sp3 hybrids due to differences in size and energy of orbitals in second-row atoms.
  • A question is raised about how to determine the appropriateness of pure hybridization versus other models for describing orbital shapes.
  • Another participant inquires about the hybridization of chlorine in HCl, indicating a broader interest in the topic of hybridization across different molecules.

Areas of Agreement / Disagreement

Participants express differing views on the nature of hybridization in H2S, with no consensus reached on whether it is best described by sp3 hybridization, partial hybridization, or a model using pure s and p orbitals.

Contextual Notes

The discussion highlights the complexity of hybridization and its dependence on molecular geometry, with participants noting that the choice of model can vary based on the specific molecule being analyzed.

ciubba
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I'm seeing conflicting answers among various textbooks. I would predict that it forms SP3 hybrid orbitals, and yet its bond angles are far from 109.5.

Edit: H2S, rather.
 
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No hybridization at all and pure sp3 are just two ends of a continuum.

For some highly symmetrical molecules (say, CH4) hybridization of the central atom is a pure sp3. But for some other molecules, like H2S, what we observe is just some partial hybridization, in which bonds are not equivalent.
 
Note also that hybridization is not a property of the molecule but entirely your personal choice of a convenient expression for the molecules wavefunction.
E.g. molecules like ethylene can equally well be described in terms of sp2+p or sp3 hybrids and water in terms of s+p or sp3 or even something intermediate.
In the case of H2S a description in terms of pure s and p orbitals makes probably more sense than the assumption of sp3 hybrid orbitals as the s and p orbitals in second row atoms differ considerably in size and energy.
 
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Borek said:
No hybridization at all and pure sp3 are just two ends of a continuum.

For some highly symmetrical molecules (say, CH4) hybridization of the central atom is a pure sp3. But for some other molecules, like H2S, what we observe is just some partial hybridization, in which bonds are not equivalent.
I see. How does one determine whether pure hybridization is a more appropriate model to describe orbital shape?
 
What about HCl, are orbitals of chlorine hybridized in that case?
 
No need for that.
 

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