Why does a 400 cos 45° force produce clockwise rotation?

13 replies · 2K views · last reply
goldfish9776
Messages
310
Reaction score
1

Homework Statement


for the 400cos45 force , i think it should rotate anticlockwise, am i right? but the book gave it is rotated counterclockwise...

Homework Equations

The Attempt at a Solution

 
Attachments
  • Textbook page showing Figure 3.27(a), a bent brace with a 400 N force at 45 degrees applied at point A, with dimensions 0.4 m and 0.1 m, and Figure 3.27(b), the equivalent resultant force and couple moment at a support.
    DSC_0075[1].JPG
    43.9 KB · Views: 419
  • Photo of a textbook page showing the calculation of resultant force FR = 962 N at 66.6°, and the moment sum MRA = 100N(0)+600N(0.4m)+(400 sin 45°)(0.8m)+(400 cos 45°)(0.3m) = 551 Nm.
    DSC_0076[1].JPG
    41 KB · Views: 435
goldfish9776 said:

Homework Statement


for the 400cos45 force , i think it should rotate anticlockwise, am i right? but the book gave it is rotated counterclockwise...

Homework Equations

The Attempt at a Solution

Uhh... "anticlockwise" and "counterclockwise" both mean the same thing, you know, "not clockwise".

RIP, Yogi Berra :cry:
 
SteamKing said:
Uhh... "anticlockwise" and "counterclockwise" both mean the same thing, you know, "not clockwise".

RIP, Yogi Berra :cry:
Typo, imo it should be in counterclockwise, right? The book gave it in clockwise direction..
 
goldfish9776 said:
Typo, imo it should be in counterclockwise, right? The book gave it in clockwise direction..
Nope, guess again.

The moment sign convention adopted by the book is a little unconventional. I prefer the right hand rule, which would make CCW moments positive.
The actual convention chosen doesn't matter, as long as you remain consistent throughout your calculations.
 
Last edited:
SteamKing said:
Nope, guess again.

The moment sign convention adopted by the book is a little unconventional. I prefer the right hand rule, which would make CCW moments positive.
The actual convention chosen doesn't matter, as long as you remain consistent throughout your calculations.
I'm wondering is my direction of 400cos 45 force correct ? Should it point to the left ?
 
SteamKing said:
Nope, guess again.

The moment sign convention adopted by the book is a little unconventional. I prefer the right hand rule, which would make CCW moments positive.
The actual convention chosen doesn't matter, as long as you remain consistent throughout your calculations.
 
Attachments
  • Diagram of a vertical rod with a horizontal arrow at its top pointing left, labelled 400cos 45, and a length of 0.3m marked along the rod, with a red curved arrow showing a rotation direction.
    hg.png
    48.9 KB · Views: 487
goldfish9776 said:
I'm wondering is my direction of 400cos 45 force correct ? Should it point to the left ?
Yes, it is correct.
 
SteamKing said:
Yes, it is correct.
then the moment should be anticlockwise , right ? by using right hand rule . I bent my finger from f to F , since it's r cross F
 
goldfish9776 said:
then the moment should be anticlockwise , right ? by using right hand rule . I bent my finger from f to F , since it's r cross F
The moment you showed in Post #6 is indeed CCW.
 
SteamKing said:
The moment you showed in Post #6 is indeed CCW.
Ok, then the book is wrong...
 
goldfish9776 said:
Ok, then the book is wrong...
No, the moment shown in the book is properly CW.

The figure you drew in Post #6 does not match the layout of forces shown in the book, and the direction of that moment is CCW.

You can't change the position of the force relative to the axis of rotation without changing the direction of the moment which is produced.
 
SteamKing said:
No, the moment shown in the book is properly CW.

The figure you drew in Post #6 does not match the layout of forces shown in the book, and the direction of that moment is CCW.

You can't change the position of the force relative to the axis of rotation without changing the direction of the moment which is produced.
I m confused now. Then can you show mew the r x f diagram in the book? I have no idea at all.
 
goldfish9776 said:
I m confused now. Then can you show mew the r x f diagram in the book? I have no idea at all.
It's Fig. 3-27(a). Point A is located about half way up the y-axis, while the 400 N force is located about 0.8m from the origin.

You don't need a lot of diagrams and whatnot to figure this out. If point A is the point about which a force causes rotation, you should be able to visualize this from a picture if you can see where the force is applied relative to point A.
 
SteamKing said:
It's Fig. 3-27(a). Point A is located about half way up the y-axis, while the 400 N force is located about 0.8m from the origin.

You don't need a lot of diagrams and whatnot to figure this out. If point A is the point about which a force causes rotation, you should be able to visualize this from a picture if you can see where the force is applied relative to point A.
since the author assume clockwise as positive here , so shouldn't the positive 400cos45 (0.3) rotate anticlockwise? i have drawn a diagram for the moment in the previous post , showing it is rotated in anticlockwise direction... i can't understand why the moment is in clockwise direction for the author...