Why Does Adding 's' Change to Subtracting 'c' in This Algebraic Expression?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 2K views
roadworx
Messages
20
Reaction score
0
Hi,

I have:

[tex]\frac{a}{b+a+s} + \frac{c*b}{(b+a+s)(c+s)}[/tex]

I can rearrange that to:

[tex]\frac{a-c}{b+a-c} * \frac{b+a}{b+a+s} + \frac{b}{b+a-c} * \frac{c}{c+s}[/tex]

Is this correct? If so, can someone tell me why the +s changes into a -c?
 
Physics news on Phys.org
roadworx said:
Hi,

I have:

[tex]\frac{a}{b+a+s} + \frac{c*b}{(b+a+s)(c+s)}[/tex]

I can rearrange that to:

[tex]\frac{a-c}{b+a-c} * \frac{b+a}{b+a+s} + \frac{b}{b+a-c} * \frac{c}{c+s}[/tex]

Is this correct? If so, can someone tell me why the +s changes into a -c?
If your goal is to combine the two rational expressions, multiply the one on the left by 1 in the form of (c + s)/(c + s). That gives you the same denominator in both expressions, so you can then add the numerators.

A +s should not change to a -c.