Why does an ideal gas have parallel isotherm and isenthalpic curves?

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Homework Statement



Why does a gas behave as ideal if the Isotherm and Isenthalp are parallel.

Homework Equations


h=u+pv
T1=T2, P1V1=P2V2

The Attempt at a Solution


[/B]
h1=u1+p1v1, h2=u2+p2v2
h2=h1 so
u1+p1v1=u2+p2v2
and p1v1=p2v2
Does that mean internal energy for an ideal gas is zero?
I don't understand. Thanks in advance!
 
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Chestermiller said:
No. It means that u1=u2
Thanks! Why would internal energy be equal for an ideal gas process??
 
ScareCrow271828 said:
Thanks! Why would internal energy be equal for an ideal gas process??
For an ideal gas, the internal energy per unit mass is a unique physical property that depends only on the temperature, irrespective of the process. So, if the temperature is the same, the internal energy is the same.