Why Does Coulomb's Unit Measurement Include Seconds?

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SUMMARY

Coulomb's unit measurement is defined as the total amount of charge carried by a current of one Ampere over one second, resulting in units of Amperes seconds rather than Amperes per seconds. This distinction arises because a coulomb represents a total quantity of charge, not a rate, similar to how energy is defined as power multiplied by time. The mathematical relationship I = dQ/dt confirms that charge (Q) is the integral of current (I) over time (t), reinforcing the concept that coulombs are cumulative. Thus, after two seconds, a current of one Ampere results in two coulombs of charge.

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If a coulumb is defined as the amount of charge carried by a current of one Ampere in a second, why is its units Amperes seconds and not Amperes per seconds?
 
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I=\frac{dQ}{dt} by definition and so Q = \int I\;dt which has a unit of (amperes x seconds)
seems obvious to me, do I understand your question correctly?
 
Yes, I see how it works mathematically. But I just thought "the amount of charge carried by a current of one Ampere in a second" was similar to the amount of charge carried by a current of one Ampere per second" so it would have units of Amperes/S
 
No because a coulomb is a total amount of charge not a rate, so after 2 seconds you have 2 coulombs.
 
yeah, another example Energy = Power x time
and Energy is not a rate, while Power is. so amount of charge is like "energy" in this analogy
 

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