Why Does Coulomb's Unit Measurement Include Seconds?

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If a coulumb is defined as the amount of charge carried by a current of one Ampere in a second, why is its units Amperes seconds and not Amperes per seconds?
 
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[tex]I=\frac{dQ}{dt}[/tex] by definition and so [tex]Q = \int I\;dt[/tex] which has a unit of (amperes x seconds)
seems obvious to me, do I understand your question correctly?
 
Yes, I see how it works mathematically. But I just thought "the amount of charge carried by a current of one Ampere in a second" was similar to the amount of charge carried by a current of one Ampere per second" so it would have units of Amperes/S
 
No because a coulomb is a total amount of charge not a rate, so after 2 seconds you have 2 coulombs.
 
yeah, another example Energy = Power x time
and Energy is not a rate, while Power is. so amount of charge is like "energy" in this analogy