Why does current through the inductor start at 20A instead of splitting?

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influx
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Why is the initial current through the inductor 20A? Surely the current splits at the junctions?
 
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It is an ideal inductor, it has a resistance of 0. The splitting still gives 20 A to the inductor.
 
mfb said:
It is an ideal inductor, it has a resistance of 0. The splitting still gives 20 A to the inductor.

So no current enters the 0.1 ohm resistor branch? Also, do we always assume its an ideal conductor in these types of questions?
 
influx said:
So no current enters the 0.1 ohm resistor branch?
Right.
Also, do we always assume its an ideal conductor in these types of questions?
To model a real inductor, we could simply add a series resistor in the sketch.
 
mfb said:
...

If no current passes through the 0.1 ohm resistor then I am assuming no current passes through the other resistors either? So effectively, when the switch is closed, the circuit consists of just the current source and the inductor?
 
mfb said:
Sure.

If the inductor did have some resistance, let's say 0.01ohms, would that mean that the 20A is split between branches?